The solution set of inequality 2 Λ X - (3 / x) + 1 ≤ 1 / 2 is 2∧[x-﹙3/x﹚+1]≤1/2

The solution set of inequality 2 Λ X - (3 / x) + 1 ≤ 1 / 2 is 2∧[x-﹙3/x﹚+1]≤1/2


2^[x-﹙3/x﹚+1]≤2^(-1)
[x-﹙3/x﹚+1]≤-1
x^2+2x-3



1、 Solve the following inequality as required. 1. Solve the inequality 2x-3 of 5 < X-1 of 2, and express the solution set on the number axis
2. Solve the inequality 2x-1-6x + 1 ≥ 5x-5, and express the solution set on the number axis


1. Solve inequality (2x-3) / 5 < (x-1) / 2
4x-6=15x-15
-27x>=-9
x



|1\4-1\2|+|1\6-1\4|+|1\8-1\6|+…… |How to do it?
\It's a fraction


1003\2008