1 2 3 4 56 7 8 9 10 11 12 13 14 15.......... 96 97 98 99 100 a B 1. Frame out the four numbers C D from the middle 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 ............... 96 97 98 99 100 a b 1. Frame out the four numbers C and D, set the minimum number as X, and express the sum of the four numbers with integral a 2. Box out the five numbers B, C and D, and let the number in the middle be y, If their sum is equal to 85, write these five digits

1 2 3 4 56 7 8 9 10 11 12 13 14 15.......... 96 97 98 99 100 a B 1. Frame out the four numbers C D from the middle 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 ............... 96 97 98 99 100 a b 1. Frame out the four numbers C and D, set the minimum number as X, and express the sum of the four numbers with integral a 2. Box out the five numbers B, C and D, and let the number in the middle be y, If their sum is equal to 85, write these five digits

1.a=x,b=x+1,c=x+5,d=x+6.
So a + B + C + D = 4x + 12
2.c=y
Then a = Y-5, B = Y-1, d = y + 1, e = y + 5
a+b+c+d+e=5y
That is, the sum of their integers is a multiple of 5
So it's not equal to 83
When 5Y = 85, y = 17
a=12.b=16,c=17,d=18,e=22.