The antonym of open and aboveboard

The antonym of open and aboveboard

Open and aboveboard [antonym]: furtive; not guilty; not deceive the darkroom; the darkroom can be deceived; frank; sinister; ulterior motives; furtive; clean and honest; selfless; honest and upright; shameless; frank; the icing on the cake

Is it better to send charcoal in the snow or to add icing on the cake?

Sending charcoal in the snow: it refers to giving material or spiritual help to others when they are in urgent need
Icing on the cake: the metaphor is good and beautiful
It depends on where it is used. You can know which one is better if you understand the meaning

Make sentences by sending charcoal in the snow

For the exhausted cotton growers and cotton managers, this is really a timely help. He read it repeatedly and tried to learn according to the methods introduced in the article, with effective results. Through the unity and hard work of the vast number of employees, he successfully completed the work task, and provided Changchun with the opportunity to prevent and resolve the financial crisis

(- 4 / 3) + 3 / 8 + / - 0.75 / + (- 5 / 1) + / - 2 / 5)

Original formula = - 3 / 4 + 3 + 3 / 8 + 3 / 4-5-1 / 2-2-5 / 8
=（3-5-2）+（-3/4+3/8+3/4-1/2-5/8）
=-4-3/4
=-4 and 3 / 4 or - 15 / 4

How much is 0.75 × 3 / 8 + 1 / 4 ÷ 8 / 3 = calculated by recurrence equation

75 × 3 / 8 + 1 / 4 △ 8 / 3
=3/4*3/8+1/4*3/8
=(3/4+1/4)*3/8
=1*3/8
=3/8

There are 5 questions in a math exam, 52 students in the class take part in the exam, and they do 181 questions correctly
There are 5 questions in a math exam. 52 students in the class participated in the exam and did 181 right questions. It is known that each student should do at least 1 question. There are 7 students who did 1 question correctly. The number of students who did 2 and 3 questions correctly is the same. There are 31 students who did 4 questions correctly. How many students do 5 questions correctly?
The calculation formula

This is a quadratic equation of two variables
Let X be the number of people doing right 5, and y be the number of people doing right 2 to 3
We get two equations
5X+4*31+2Y+3Y+7=181
2Y+7+X+31=52
The first equation gives x + y = 10
The second gives x + 2Y = 14
The solution is x = 6, y = 4

In a certain year, 52 students in the class took part in five questions in the math exam, and they did 181 right questions in total. It is known that each person did at least one right question. There were seven people doing one right question, six people doing all five right questions, and there were as many as two and three right questions?

Suppose there are x people doing 2 and 3 questions correctly, then there are 52-7-6-2x people doing 4 questions in the team
1x7+5x6+2x+3x+4(52-7-6-2x)=181
7+30+5x+156-8x=181
193-3x=181
3x=12
x=4
There are 52-7-6-2x = 39-2x4 = 31 people doing four questions in the team

52 people participated in a certain exam. The statistics of the number of people who did each question correctly are as follows (in the supplementary part of the question)
The number of questions: 1, the number of correct: 48; 2, 46; 3, 42; 4, 32; 5, 13
Each person should do at least one right question. There are seven people who do only one right question and six people who do all five right questions. The number of people who do two right questions is as much as that of people who do three right questions. How many people do four right questions?
And we need to use the indefinite equation

Suppose that the person who does the four questions correctly is x, and the person who does the two rivers and three roads correctly is y
Then do the right total number of questions 48 + 46 + 42 + 32 + 13 = 7 * 1 + 6 * 5 + 2 * y + 3 * y + 4 * X
The total number of examinees is 52 = 7 + 6 + 2Y + X
Combine the above two equations to get binary linear equations, very good solution, solve it yourself!

The answers to 13, 14 and 15 questions in 52 aspects of Mathematics
Give a lot of points

Not everyone has the content of "practice and test seven times mathematics", so it is difficult to find the answer to the question
It is suggested that you close the question and ask again, and write down the questions you want to solve
Or you send me the question directly, I can help you solve the problem online

In a certain math exam, 52 students in the class took part in five questions and did 181 right questions. It is known that each student did at least one right question. There were 7 students doing one right question and 6 students doing five right questions. There were as many students doing two and three right questions, so how many students were doing four right questions?

The number of people doing right 4 is 52-7-6-2x, that is to say, the number of people doing right 4 is 39-2x. According to the passage, we can get the equation: 1 × 7 + 2x + 2x + 3x + 3x + 3x + 3x + 3x + 3x + 3x + 3x + 4 (39-2x) + 5 × 6 = 181, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp it's not easy;           193-3x=181，                         3x=12，                    &X = 4, so the number of people doing the right 4 courses is 39-2 × 4 = 39-8 = 31. A: the number of people doing the right 4 courses is 31