What is the conversion between XG and / RPM?

Under the rotating radius of 3cm, the speed of centrifugal force per 300xg is about 2990rpm
(this is my own conversion)
When a particle (biomacromolecule or organelle) is subjected to centrifugal force under high-speed rotation, the centrifugal force "F" is defined by the following formula, namely:
　　F = m•a = m•ω2 r
A - acceleration of particle rotation, M - effective mass of settling particle, ω - angular velocity of particle rotation, R - radius of particle rotation (CM)
In general, centrifugal force is usually expressed by the multiple of the earth's gravity, so it is called relative centrifugal force "RCF". Or it is expressed by the number multiplied by "g", for example, 25000 × g, which means that the relative centrifugal force is 25000. Relative centrifugal force refers to that in the centrifugal field, the centrifugal force acting on particles is equivalent to the multiple of the earth's gravity, and the unit is the acceleration of gravity "g"
The relative centrifugal force of RCF can be calculated as follows: RCF = 1.119 × 10-5 × (RPM) 2R
(RPM revolutions per minute, R / min)
It can be seen from the above formula that the RCF and RPM can be converted to each other as long as the rotation radius R is given. However, due to the difference of the shape and structure of the rotating head, the distance between each point of the centrifugal tube from the nozzle to the bottom of the tube and the rotation axis of each centrifuge is different. Therefore, the average radius "RA V" is used to replace the specified rotation radius in the calculation: RA v = (r min + Rmax) / 2
In general, the rotational speed "RPM" is often used in low speed centrifugation, and "g" is used in high speed centrifugation. When calculating the relative centrifugal force of particles, it should be noted that the distance "R" between the centrifugal tube and the center of the rotating shaft is different, that is, the centrifugal force is different if the position of the settling particles in the centrifugal tube is different, Usually, the multiple of gravity "× g" is always used instead of "RPM", because it can truly reflect the centrifugal force and its dynamic change of particles at different positions in the centrifuge tube. The data of centrifugal force in scientific literature usually refers to its average value (RCFA V), that is, the centrifugal force at the midpoint of the centrifuge tube
In order to facilitate the conversion between rotational speed and relative centrifugal force, Dole and cotzias made a nomograph of the relationship among rotational speed "RPM", relative centrifugal force "RCF" and rotation radius "R" by using RCF formula. The diagram method is more convenient than the formula method, Then draw a straight line between the two points, and the intersection point on the RCF scale in the figure is the corresponding value of the relative centrifugal force. Note that if the known rotation value is on the right side of the RPM scale, the value on the right side of the RCF scale should be read. If the rotation value is on the left side of the RPM scale, the value on the left side of the RCF scale should be read

If f (x) is an odd function on R, f (- x) = f (x-1), can we prove that the period of function is 2?

It can be seen from the proposition that f (x) + F (- x) = 0. And f (- x) = f (x-1) = = = > F (x-1) + F (x) = 0. = = = > F (x-1) = f (x + 1) = = = > F (x-1) = f (x + 1) = = = = > F (x) = f (x + 2).. function f (x) is a periodic function with period 2

How many rpm is 70 RPM of motor

70 revolutions per minute is equal to 70 rpm
RPM means revolutions per minute

If the opening of quadratic function image is upward and the symmetry axis is x = 2, then f (2), f (3) and f (4) are the same

According to the meaning of the title
When x > = 2, y increases with the increase of X
∴f(2)

As shown in the figure, why is the angular velocity of a and B not equal? Is it not coaxial rotation? Is it not coaxial rotation that makes the angular velocity equal?

A. The centripetal acceleration is equal to mgtan Xita, the centripetal acceleration is equal to the square radius of the angular velocity, and the radii of a and B are not equal, so the angular velocity of the two balls is not equal

It is known that the symmetry axis of the image of quadratic function y = (T + 1) + 2 (T + 2) x + 3 / 2 is x = 1. (1) find the analytic expression of quadratic function; (2) translate the image of quadratic function y = (T + 1) + 2 (T + 2) x + 3 / 2 to the right for 2 unit lengths, and then to the down for 2 units, and get the analytic expression of quadratic function as follows____ (3) the image of quadratic function y = (T + 1) + 2 (T + 2) x + 3 / 2 is rotated 180 ° around the vertex to get a new parabola. Proof: when the vertex of the new parabola moves on the original parabola, the new parabola must pass the vertex of the original parabola

(1) the axis of symmetry of the parabola y = (T + 1) + 2 (T + 2) x + 3 / 2 is x = 1,
That is - 2 (T + 2) / [2 (T + 1)] = 1, t = - 3 / 2,
∴Y=-1/2X^2+X+3/2,
(2) y = - 1 / 2 (x-1) ^ 2 + 2, vertex coordinates: (1,2),
When the vertices (1,2) are shifted to the right and then down by 2 units, they are (3,0),
That is, y = - 1 / 2x ^ 2 + 3x-9 / 2
(3) the new parabola y = 1 / 2 (x-3) ^ 2, when the vertex coordinates move on y = - 1 / 2x ^ 2 + X + 3 / 2, the,
Let the vertex coordinates be (m, - 1 / 2m ^ 2 + m + 3 / 2),
∴Y=1/2(X-m)^2-1/2m^2+m+3/2
=1/2X^2-mx+1/2m^2-1/2m^2+m+3/2
=1/2X^2-mX+m+3/2
When x = 1, y = 1 / 2-m + m + 3 / 2 = 2,
That is, the new parabola passes through (1,2), that is, the vertex of the original parabola

Given that t is a real number, let the minimum value of quadratic function y = x ^ 2-2tx T-1 of X be f (T), and find the maximum and minimum value of F (T) on t greater than or equal to 0 and less than or equal to 2

If the quadratic function is y = x ^ 2-2tx + T-1 = (x-t) ^ 2-T ^ 2 + T-1
So when x = t, the function gets the minimum f (T) = - T ^ 2 + T-1
F '(T) = - 2T + 1, the stationary point t = 1 / 2
f(0)=-1,f(1/2)=-3/4,f(2)=-3
So the maximum f (1 / 2) = - 3 / 4 and the minimum f (2) = - 3

The symmetry axis of quadratic function f (x) is x = 2, and f (x)
(1) The size relationship between F (- 3) and f (1)
(2) The size relationship between F (- 3) and f (3)

The axis of symmetry of F (x) is x = 2
F (2) should be the maximum or minimum value of the function
f(x)f(x)

A quadratic function, a + B + C or A-B + C, 2A + B, 2a-b, how to judge whether it is greater than or less than 0, please use the method of looking at the axis of symmetry

Quadratic function y = ax & # 178; + BX + C,
When x = 1, y = a + B + C
When x = - 1, y = A-B + C,
As for the latter two, 2A + B and 2a-b, they are determined by the opening direction of the parabola and the position of the axis of symmetry and the straight line x = 1 or the straight line x = - 1,
Why don't you explain the specific topic again and ask me

In quadratic function, when B is equal to 0, how to calculate the axis of symmetry? For example, the axis of symmetry of - 3x2 (square) + 5
What about vertex coordinates?

The square of X should be expressed as: x ^ 2;
In quadratic function y = ax ^ 2 + BX + C, when B is equal to 0, the axis of symmetry is Y axis;
The formula for calculating the symmetry axis of quadratic function y = ax ^ 2 + BX + C is x = - B / 2A. Obviously, when B = 0, x = 0, that is, the symmetry axis is Y axis;
Add: in your example, the vertex coordinates are (0,5);
In the quadratic function y = ax ^ 2 + BX + C, the abscissa of the vertex is the axis of symmetry. When B = 0, the ordinate of the vertex is C;
Calculation method of vertex coordinates:
[method 1]
The calculation formula of vertex coordinates (x, y) of quadratic function y = ax ^ 2 + BX + C is: x = - B / 2a, y = (4ac-b ^ 2) / 4A;
[method 2]
When the symmetry axis is known, the corresponding value obtained by the function is the vertex ordinate; for example, in your example, the symmetry axis has been calculated as y axis, that is, x = 0, then the ordinate is 5 by directly substituting x = 0 into the function y = - 3x ^ 2 + 5;

What is the conversion between XG and / RPM?