Why is the angular velocity of coaxial transmission equal? Also, belt, chain rotation, gear rotation, friction rotation, why their linear speed will be equal?

Why is the angular velocity of coaxial transmission equal? Also, belt, chain rotation, gear rotation, friction rotation, why their linear speed will be equal?


Coaxial rotating parts (gears, etc.) only fixed on the shaft, and the shaft does not rotate relative, will be the same speed rotation, that is, the angular speed is equal. Belt, chain speed (value) is fixed, so their linear speed is equal. Otherwise, belt, chain will be elongated, broken, there will be no normal



What does angular velocity, linear velocity mean


Angular velocity: the radian that connects the radius of a moving particle and the center of a circle and turns in unit time is called "angular velocity". The unit of angular velocity is radians per second, which is read as radians per second. It is a physical quantity that describes the speed and direction of rotation of an object or a particle around another particle. The time change rate of angular displacement of an object is called instantaneous angle



Concept and calculation of linear velocity and angular velocity in geography
1、 It's better not to talk about the concept of physics, but to explain it in more popular words;
2、 About calculation: the average radius of the earth is 6371 km, and the linear velocity at 30, 45 and 60 degrees latitude is calculated


Linear speed is how many kilometers per hour, angular speed is how many angles per hour
If you don't know how to calculate it, you can recite the conclusion: linear velocity - 30 degree latitude is the root of 2 / 2 of the equator, 3, 45 degree is the root of 2 / 2 of the equator, 2, 60 degree is 1 / 2 of the equator



What are the definitions of linear velocity and angular velocity?


Linear velocity refers to the instantaneous velocity of an object in circular motion. It is a scalar. Angular velocity refers to the angle of a wonderful clock. High school still regards it as a scalar



Determine the symmetry axis of quadratic function, x = - B / (2a), determine the center point of interval H = (x1 + x2) / 2
What does that mean to determine the center of a district? Or what is the center of a district?
Man, help me


It is the center point of the function at the intersection of the x-axis, and the line passing through the point perpendicular to the x-axis is the axis of symmetry~



The meaning of symmetry axis X = a in quadratic function
To explain in words, isn't x = 4 a point? How can it represent a straight line? What's its concept?


X = a is a line perpendicular to the X axis
It's actually x + 0 * y = a
Represents the point (x, y)
Where x = a, y = any real number
So x = a is a straight line perpendicular to the X axis



Is the axis of symmetry of a quadratic function of one variable parallel to the Y axis?


Because every x-value of a function has a y-value corresponding to it, only two x-values of a quadratic function of one variable have the same y-value. In order to make the distance between the two x-values and the axis of symmetry equal, only a line parallel to the y-axis can do it. (because if the axis of symmetry is parallel to the x-axis, it means that an x-value corresponds to two y-values, So you can write the axis of symmetry x = a ⊥ x directly



For two simple harmonic vibrations with the same direction and frequency, the combined vibration amplitude is 20cm, and the phase difference with the first simple harmonic vibration is π / 6. If the amplitude of the first simple harmonic vibration is 10 √ 3cm, the amplitude of the second simple harmonic vibration is


10√3sin(w*t)+A*sin(w*t+a)=20sin(w*t+π/6)
A=10cm



How to find the phase difference of two simple harmonic motions in this graph?


Let y = sin α X and T = 0.4s
The light color is sin (α x + π / 2), and the period is 0.4s
Then the phase difference is | α x + π / 2 - α x | = π / 2



The amplitude of a particle in harmonic motion is 4cm, and the period is 0.4s. What is the displacement and the distance of the particle after 2.5s from the equilibrium position?


The period of the oscillator is t = 0.4s, time t = 2.5s = 614t; because it starts to vibrate from the equilibrium position, after 2.5s, the oscillator reaches the maximum displacement, and the displacement is x = a = 4cm. In 2.5s, the distance of the oscillator is s = 6.25 × 4A = 6.25 × 4 × 4cm = 100cm