How to judge the parity of y = SiNx cos + 1 If the problem, please say in detail, the mathematical foundation is not good y=sinx-cosx+1

How to judge the parity of y = SiNx cos + 1 If the problem, please say in detail, the mathematical foundation is not good y=sinx-cosx+1

Replace X in the equation with - X and substitute it into the original equation
y1=sin(-x)-cos(-x)+1=-sinx-cosx+1
Compared with the original equation, if y is not equal to Y1 or - Y1, then it is not odd or even

Judging the parity of function f (x) = | SiNx | + cosx

f（-x）=｜sin（-x）｜+cos（-x）=｜sinx｜+cosx=f（x）
So f (x) is an even function

Draw the graph of the function y = | 3x-1 | and use the graph to answer: when k is the value, the equation | 3x-1 | = k has no solution? Is there a solution? There are two solutions?

The image of y = | 3x-1 | is as follows: when k < 0, | 3x-1 | = k has no solution; when k = 0 or k > 1, | 3x-1 | = k has one solution; when 0 < K < 1, the equation | 3x-1 | = k has two solutions

Given the function f (x) = - x square + 2 | x | + 3 (1), f (x) is expressed in the form of piecewise function (2), and the image of F (x) is drawn
(3) Write the monotonicity of F (x) according to the image

1. When x ＞ 0, f (x) = x ^ 2 + 2x + 3 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; when x = 0, f (x) = 3 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; when x ＜ 0, f (x) = x ^ - 2x + 3 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & n