The coordinates of the intersection of the image of the linear function y = √ 2x + √ 3 with the X axis and Y axis, and the area of the triangle enclosed by the coordinate axis

The coordinates of the intersection of the image of the linear function y = √ 2x + √ 3 with the X axis and Y axis, and the area of the triangle enclosed by the coordinate axis

Substituting x = 0, y = √ 3, so the intersection point with y axis is (0, √ 3)
Substituting y = 0, √ 2x + √ 3 = 0, x = - √ 6 / 2. So the intersection point with X axis is (- √ 6 / 2,0)
The bottom of the right triangle surrounded by the coordinate axis is √ 6 / 2, and the height is √ 6
So the area is: 1 / 2 ×√ 6 / 2 ×√ 3 = 3 √ 2 / 4

It is known that the function y = (M-3) x to the power of M-8 + 3 is a first-order function

y=(m-3)x^(m²-8)+3
m²-8=1
m²=9
m=±3
∵ M-3 is not equal to 0
Ψ m cannot be equal to 3
∴m=-3
The analytic formula of a function: y = - 6x + 3

Why is the function y = (M + 3) times the 2m + 1 power of x plus 4x + 5 (x is not equal to 0) a linear function?

When 2m + 1 = 1, i.e. M = 0, it is a linear equation
In other words, when 2m + 1 = 0, that is, when m = - 1 / 2, the equation is also a linear equation

When m = what, y = (M + 3) x ^ 2m + 1 + 4x-5 is a linear function
(M + 3) x ^ 2m + 1 is one
+4x-5 is part of it

If x is a function of degree, then x is of degree 1
There's 4x in the back
So x ^ (2m + 1) is once or zero
So 2m + 1 = 1 or 2m + 1 = 0
m=0,m=-1/2