Given the function f (x) = x 2 + ax + 3, when x ∈ [- 2,2], f (x) ≥ A is constant, and the minimum value of a is obtained

Given the function f (x) = x 2 + ax + 3, when x ∈ [- 2,2], f (x) ≥ A is constant, and the minimum value of a is obtained

Let the minimum value of F (x) on [- 2, 2] be g (a), then the minimum value of a satisfying g (a) ≥ A is obtained. The formula is f (x) = (x + A2) 2 + 3 − A24 (| x | ≤ 2) (1) when − 2 ≤− A2 ≤ 2, i.e. - 4 ≤ a ≤ 4, G (a) = 3 − A24, from the solution of 3-a24 ≥ a, ■ - 4 ≤ a ≤ 2; (2) when − A2 ≥ 2

Let a be a normal number greater than 0, and the minimum value of F (x) = (1 / SiNx ^ 2) + (A / cosx ^ 2) is 9, then the value of a is equal to 0

Let y = cosx ^ 2,0

It is known that the maximum value of the function y = - x2 + ax-a / 4 + 1 / 2 on 0 ≤ x ≤ 1 is 2. Please specify the value of A,

Because the opening is downward, the quadratic function has a maximum
Find the axis of symmetry - 2A / b = (A-1) / 8,
Discuss whether the axis of symmetry is 0 ≤ x ≤ 1, left, right, or between
Can get three numbers, and then according to the need to exclude it