Contact us
Choose a category below so we can get back to you as quickly as possible.
設f(x)在[-2,2]上的最小值為g(a),則滿足g(a)≥a的a的最小值即為所求.配方得f(x)=(x+a2)2+3−a24(x≤2)(1)當−2≤−a2≤2時,即-4≤a≤4時,g(a)=3−a24,由3-a24≥a解得∴-4≤a≤2;(2)當−a2≥2時...
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.