Given the function y = x / K (k is a constant not equal to zero), the value of Y decreases as the value of x increases. Point a (3, K-2) calculates the value of K on the image of this function

Given the function y = x / K (k is a constant not equal to zero), the value of Y decreases as the value of x increases. Point a (3, K-2) calculates the value of K on the image of this function

Because the value of function y decreases with the increase of X, so 1 / K < 0, so k = - 1

1. In the function y = (m2-m) xm2-2, when m=_____ It is an inverse scale function
2. Among the following four functions, the one that has a common point with the image of the function y = - 4 / X is ()
A.y=2x/3 B.y=2/3x C.y=-4x D.y=4x
3. In the agreed rectangular coordinate plane, if there is no intersection between the straight line y = K1 (subscript) x and the hyperbola y = K2 (subscript) / x, then the relationship between K1 and K2 must be ()
A. K10 c.k1 > K2 d.k1, K2 different sign

1. In the function y = (m2-m) xm2-2, when m=__ -1___ It is an inverse scale function
Because it's an inverse scale function
The exponent of X is - 1
The coefficient of X is not zero
m^2-2=-1
m^2=1
m=±1
m^2-m≠0
m≠0,1
∴m=-1
2. Among the following four functions, the one that has a common point with the image of function y = - 4 / X is (c) a.y = 2x / 3 b.y = 2 / 3x C.Y = - 4x D.Y = 4x
-4/x=2x/3
2x^2=-12
unsolvable
-4/x=2/3x
2x=-12x
unsolvable
-4/x=-4x
1=x^2
There are solutions
4x=-4/x
x^2=-1
unsolvable
If there is no intersection between the straight line y = K1 (subscript) x and the hyperbola y = K2 (subscript) / x, then the relationship between K1 and K2 must be (d) a.k10 c.k1 > K2 d.k1, K2 different sign
Only when two hyperbolas are not in the same quadrant, there is no intersection

When x is less than 0, y increases with the increase of X, then the value range of M is-
2 when k is greater than 0 and X is less than 0, y = K / X is in the -- quadrant

1、
Y increases with the increase of X
So the coefficient is less than 0
1-2m1/2
2、
k>0
So y = K / X in the first and third quadrants

If the point P (2m-3,1) is on the image with inverse scale function y = 1 x, then M=______ ．

∵ point P (2m-3, 1) on the image of inverse scale function y = 1 x, ∵ (2m-3) × 1 = 1, the solution is m = 2