How to find the intersection point of inverse proportion function and positive proportion function

How to find the intersection point of inverse proportion function and positive proportion function

y=kx,y=m/x
The intersection point is the common solution of the two equations
There are KX = m / x, X & # 178; = m / K, x = ± √ (M / k)
y=±k*√(m/k)=±√(mk)

Excuse me, I know the analytic expressions of positive proportion function and inverse proportion function, how to find the intersection coordinates
For example
The positive scaling function is y = 2x
The inverse scale function is y = 5 / X
How to find the coordinates of their intersections

Find the coordinates of the intersection, that is, y is equal,
Then 2x = 5 / X
Then the square of x = 5 / 2
Then the ± root of X is 10 / 2
Take ± root 10 / 2 into y = 2x,
Get X1 = root 10
X2 = - root 10, so the intersection coordinates are (root 10 / 2, root 10) and (- root 10 / 2, - root 10)

As shown in the figure, in the parallelogram aobc, the diagonal intersects at the point E, and the hyperbola y = KX (k > 0) passes through two points a and E. if the area of the parallelogram aobc is 18, then K=______ ．

Let a (x, y) be a parallelogram, let a (E) be a parallelogram, let a (E) be a parallelogram, let a (E) be a parallelogram, let a (E) be a parallelogram, let a (E) be a parallelogram, let a (E) be a parallelogram, let a (E) be a parallelogram, and let a (E) be a parallelogram =Therefore, the answer is: 6

If point P (M + 3, - m-1) is on the angular bisector of the third quadrant of the rectangular coordinate, then M=

On the bisector of three quadrants in rectangular coordinates
Then M + 3 = - M-1
The solution is m = - 2

In the same rectangular coordinate system, there is no intersection between the positive scale function y = K1 and the inverse scale function xy = K2 / X. please determine the value range of the product of two constants k1k2

K1K2O
Because there are no intersections
So k1k2

The definition field of function y = 1 / 1-tan2x is?

1-tan2x ≠ 0 (denominator is not 0), and 2x ≠ K π + π / 2 (tan2x should be meaningful)
Tan2x ≠ 1, and 2x ≠ K π + π / 2
Then 2x ≠ K π + π / 4, and 2x ≠ K π + π / 2
So x ≠ K π / 2 + π / 8, and X ≠ K π / 2 + π / 4 (K ∈ z)

Please judge the boundedness of the function in the domain y = x / (1 + x ^ 2),

The domain is r
When x = 0, y = 0
x> 0, because (1-x) ^ 2 > = 0, i.e. 1 + x ^ 2-2x > = 0, we get: X

Can you help me explain the meaning of some symbols in this mathematical function?
In a quadratic equation AX2 + BX + C = 0 (a > 0)
In order to ensure that two different real roots are greater than one, the following conditions should be met:
①Δ＞0
②f(1)＞0
③-b/2a＞1
What does f (1) > 0 mean in the second term?
Also, how to understand the whole above?

① Δ is the discriminant = B & sup2; - 4ac
② F (1) > 0 is to bring 1 into the quadratic equation AX2 + BX + C = 0 (a > 0)
③ - B / 2a is the symmetry axis of the equation image
Is that ok
In a quadratic equation AX2 + BX + C = 0 (a > 0)
Ensure that two distinct real roots are greater than one
It can be seen from the image
① When Δ > 0, there is an intersection between the image and the x-axis
② F (1) > 0, ③ - B / 2A > 1, that is, the minimum root of the equation > 1
See?

Seek master to explain the meaning of an ISERROR function formula
=IF(ISERROR(G16/(E16+F16)*100),"---",G16/(E16+F16)*100)
This formula is a formula for calculating percentage

Iserror() function is mainly used to determine whether the formula running result is wrong. It is often used in error prone formulas. For example, when the search value of vlookup function cannot be found in the search area, the error value of "# - N / a" will appear: = vlookup ("Zhang San", a: B, 2,0) when column a in the table has no cell with the content of "Zhang San"

Who can give me an example to explain the definition of function limit
definition:
If for any given positive number γ, there is always a positive number m such that when all | x | > m, | f (x) - A|

f(x)=1/x
A=0
In other words, as long as | x | is large enough, then | f (x) - a | = 1 / | x | can be arbitrarily small, for example, when | x | > m = 1 / γ, 1 / | x ||