1. It is known that the equation m (x-1) = 5x-2 about X has a unique solution?

m(x-1)=5x-2
mx-m=5x-2
(m-5)x=m-2
If there is a unique solution, then the coefficient of X is not equal to 0
m-5≠0
m≠5

Given that x is less than 5 / 4, find the maximum value of the function y = 4x-2 + 1 / (4x-5)

Y=4X-2+1/（4X-5）=（4X-5）+1/（4X-5）+3
∵X

Known x

High school mathematics known x ≤ 4 / 5, find the maximum value of (16x ^ 2-28x + 11) / (4x-5). Thank you

x> 5 / 4, find the minimum value of the function y = (16x ^ 2-28x + 11) / 4x-5

x> If y = (16x & # 178; - 28x + 11) / (4x-5) = (4x-2) + 1 / (4x-5) = (4x-5) + 1 / (4x-5) + 3 ≥ 2 + 3 = 5, then if and only if 4x-5 = 1 / (4x-5), that is, (4x-5) &# 178; = 1,4x-5 = 1,4x = 6, x = 3 / 2, the equal sign is

Square of x plus 4x minus 3 = 0
Find its two real roots

If point P (x, y) satisfies: √ 3-y = 0, Y > = 0, then what is the maximum value of the square of x plus the square of Y minus 4x?

Point P (x, y) satisfies: √ 3x-y = 0, Y > = 0,
The feasible region is △ OAB and its interior, where a (- 2,0), B (1, √ 3), a (- 2,0), B (1, √ 3), a (- 2,0), B (1, √ 3), a (- 2,0), B (1, √ 3), a (- 2,0), B (1,
The longest line between point C (2,0) and the point on the feasible region is ca,
The maximum value of x ^ 2 + y ^ 2-4x = (X-2) ^ 2 + y ^ 2-4 = 12
The distance from point C to line √ 3x-y = 0 d = 2 √ 3 / 2 = √ 3,
The minimum value of x ^ 2 + y ^ 2-4x = (X-2) ^ 2 + y ^ 2-4 = - 1

If the maximum value of the parabola y = - x2 + 4x + k is 3, then K=______ ．

The maximum value of ∵ parabola y = - x2 + 4x + k is 3, ∵ 4K − 16 − 4 = 3, ∵ k = - 1

If the maximum value of the parabola y = - x2 + 4x + k is 3, then K=______ ．

The maximum value of ∵ parabola y = - x2 + 4x + k is 3, ∵ 4K − 16 − 4 = 3, ∵ k = - 1

If x > 0, Y > 0 and 4x + 3Y = 12, then the maximum value of XY is ()
A. 1B. 2C. 3D. 4

∵ x > 0, Y > 0, ∵ 4x · 3Y ≤ (4x + 3y2) 2 = 36 (if and only if 4x = 3Y = 6, the equal sign holds) ∵ XY ≤ 3, so C is selected

1. It is known that the equation m (x-1) = 5x-2 about X has a unique solution?