The solution of inequality 2 (x − 1) − 5 − 4x + 1 − 15 > 1 is______ ．

The solution of inequality 2 (x − 1) − 5 − 4x + 1 − 15 > 1 is______ ．

The original inequality can be − 2 (x − 1) 5 - − 4x − 115 ＞ 1, the denominator can be removed to get - 6 (x-1) - (- 4x-1) ＞ 15, - 2x ＞ 8, X ＜ - 4. So the answer is: X ＜ - 4

|X & # 178; - 4x-2 | 2 solution inequality
Same topic

-2

Square of solving equation 3x + 4x-1 = 0

The square of 3x + 4x-1 = 0 x = (- 4 ± √ (4 * 4 + 4 * 3 * 1)) / (2 * 3) x = (- 4 ± √ 28) / 6 x = (- 2 ± √ 7) / 3

x+1.5x=7500 x-0.85x=3 4x-1.2=74

x+1.5x=7500
2.5x=7500
x=3000
x-0.85x=3
0.15x=3
x=20
4x-1.2=74
4x=74+1.2
4x=75.2
x=9.4

2X ^ 2-36x + 279 in 3

Now we draw the image of function y = 2x ^ 2-36x + 279 in the coordinate system. The vertex coordinate of the image of the quadratic function is (9117), and its image is a decreasing function in (-, 9) and an increasing function in (9, +,). Therefore, when 3

How to solve (36x-3) - (10x + 2) = 4x

（36x-3）-（10x+2）=4x
36x-3-10x-2=4x
36x-10x-4x=3+2
22x=5
x=5/22

Solve the univariate cubic equation 4x ^ 3-24x ^ 2 + 48x-32 = 0,
It's better to have a process,

4x^3-24x^2+48x-32=0
x^3-6x^2+12x-8=0
x^3-2x^2-4x^2+12x-8=0
x^2(x-2)-4(x^2-3x+2)=0
x^2(x-2)-4(x-1)(x-2)=0
(x-2)(x^2-4x+4)=0
(x-2)^3=0
x=2

The solution equation: 4x ± 2 (36x) = 120
4x±2(36–x)=120

4x±2(36–x)=120
Divide both sides of the equation by 2 to get:
2x±(36–x)=60
Expand the brackets to get:
2X + 36-x = 60 or 2x-36 + x = 60
X + 36 = 60 or 3x-36 = 60
X = 60-36 = 24 or 3x = 60 + 36 = 96
That is, x = 24 or x = 32

(x 10 1) (x 10 2) (x 10 3) (x 10 4) 10 1 is a complete square formula! How to find the complete square?

（x+1)(x+2)(x+3)(x+4)+1
= （x+1)(x+4)(x+2)(x+3) + 1
= (x^2 + 5x +4)(x^2 + 5x + 6) + 1
= (x^2 + 5x)^2 + 10(x^2 + 5x )+25
=(x^2 + 5x + 5)^2
It has been proved

If the square of X is ten MX-15 = (x x x 3) (x x x n), find the value of M

Expand:
Square ten of X MX-15 = square ten of X (3 + n) x + 3N
So:
m=3+n
3n=-15
The solution is n = - 5
So, M = 3 + (- 5) = - 2