When inequality 2 ≤ x2 + PX + 10 ≤ 6 has exactly one solution, the value of real number P is______ ．

When inequality 2 ≤ x2 + PX + 10 ≤ 6 has exactly one solution, the value of real number P is______ ．

Let y = x2 + PX + 10, then according to the meaning of the problem, there is only one common point between the image of quadratic function y = x2 + PX + 10 and the image of function y = 6, so the equation x2 + PX + 10 = 6, that is, X2 + PX + 4 = 0 has only one root, △ = p2-16 = 0, and the solution is p = - 4 or P = 4

Given the set a = {x | x-a | ax, a ＞ 0}, if logax ＞ 0 is constant on a, then the maximum value of a is______ ．

Inequality: | x-a | ax {- ax ＜ x-a ＜ ax, when a ＞ 1, we get x ＞ AA + 1, at this time, logax ＞ 0 can not be constant on a; when 0 ＜ a ＜ 1, we get: AA + 1 ＜ x ＜ AA − 1, if logax ＞ 0 is constant on a, then − AA − 1 ≤ 1 {a ≤ 12. Then the maximum value of a is 12. So the answer is: 12

In order to alleviate the traffic pressure, a special railway is planned to be built, and a train is used as a public transport vehicle. It is known that if the train drags 4 cars each time, it can go back and forth 16 times a day: if it drags 7 cars each time, So it can go back and forth 10 times a day. It is known that the number of back and forth every day is a function of the number of cars towed by the locomotive every day, and each car can carry 110 passengers at a time. Question: how many times does this train go back and forth every day? How many cars can be towed each time to carry the largest number of passengers? Try to find out the maximum number of people per day?

Let the number of round trips per day be a function of the number of cars towed by the front of the car each time
y=ax+b
4 and 16, 7 and 10
y=-2x+24
Let m be the number of passengers
M=110*xy
Simultaneous solution with the above formula
M=220(12-x)*x
When x = 6, m max = 220 * 36 = 7920

Please answer the math problems of grade one in detail, thank you! (13:17:28:21)
The fifth power of X + the third power of B x + C X-5, when x equals - 3, y equals 7, then when x = 3, the value of Y equals 7

First of all, you substitute x = - 3 into the original formula 7 = - 243-27b-3c - 5-27b - 3C = 5 + 7 + 243-27b - 3C = 255 divided by - 39B + C = - 85, so C = - 85-9b, so the original formula is equal to the fifth power of X + B, the third power of X + (- 85-9b) X-5, and then calculate 243 + 27b + (- 85-9b) 3 - 5 = 24 when x = 3