A mathematics problem of senior two, about the complex number It is known that the equation x ^ 2 + (K + 2I) x + 2 + ki = 0 has a real root. Find the real root and the value of the real number K There is a similar one: If the equation x ^ 2 + (1 + 2I) x - (3m-1) I = 0 has a real root, then the pure imaginary number M=_______ In the first, I can't, but in the second, I calculate the value of △ as (1 + 2I) ^ 2 + 4 (3m-1) I = 1 + 4i-4 + 12mi-4i = - 3 + 12mi Is that right? But the answer to the second question is m = I / 12 Who can answer that

A mathematics problem of senior two, about the complex number It is known that the equation x ^ 2 + (K + 2I) x + 2 + ki = 0 has a real root. Find the real root and the value of the real number K There is a similar one: If the equation x ^ 2 + (1 + 2I) x - (3m-1) I = 0 has a real root, then the pure imaginary number M=_______ In the first, I can't, but in the second, I calculate the value of △ as (1 + 2I) ^ 2 + 4 (3m-1) I = 1 + 4i-4 + 12mi-4i = - 3 + 12mi Is that right? But the answer to the second question is m = I / 12 Who can answer that

First: x ^ 2 + (K + 2I) x + 2 + ki = 0
（x^2+kx+2)+(2x+k)i=0
So x ^ 2 + KX + 2 = 0 and 2x + k = 0
The solution is x = positive and negative root sign 2, k = negative and positive root sign 2
Second: x ^ 2 + (1 + 2I) x - (3m-1) I = 0
（x^2+x-3mi）+(2x+1)i=0
So x ^ 2 + x-3mi = 0 and 2x + 1 = 0
The solution is x = - 1 / 2, M = I / 12

English
Mike () health food. Is it

It's milk. You misspelled the milk

What is the complex number in mathematics?

The complex number is an extension of the real number. A new number set is established by introducing the imaginary number unit I. the stipulation of the imaginary number unit is: I ^ 2 = - 1, I can perform four operations with the real number, so as to obtain the number in the form of Z = a + Bi (a, B belong to the real number). When B = 0, it represents the real number, and when B is not equal to 0, it represents the imaginary number