Can the seventh power of 36 - the twelfth power of 6 be divisible by 42

Can the seventh power of 36 - the twelfth power of 6 be divisible by 42

36^7-6^12
=6^14-6^12
=6^12(6^2-1)
=6^12*7*5
∵ 36 ^ 7-6 ^ 12 has factors of 6 and 7
It can be divided by 42

It is proved that the seventh power of 36 and the twelfth power of 6 can be divisible by 120 by factorization
It is proved by factorization that the seventh power of 36 and the twelfth power of 6 can be divisible by 120

=The 14th power of 6 - the 12th power of 6
=12 times of 36 × 6 - 12 times of 6
=12 times of 35 × 6
=9 times of 35 × 6 × 36 × 6
=9 times of 120 × 63 × 6
The seventh power of 36 and the twelfth power of 6 can be divided by 120

If the solution set of x-a > 2 is x > 1, what is the power of a to 2010

x-a>2
x>2+a
The solution set is x > 1
therefore
2+a=1
a=-1
a^2010=(-1)^2010=1

If the solution set of the inequality 2x-a > 1 b-X > 0 about X is - 1

2x-a>1 b-x>0
x>(a+1)/2,x