Decomposition factor: 20A (a-2b) ^ 2-12 (a-2b) ^ 3, where a = - 9, B = 3

Decomposition factor: 20A (a-2b) ^ 2-12 (a-2b) ^ 3, where a = - 9, B = 3

=（a-2b)^2[20a-12(a-2b)]
=(a-2b)^2[20a-12a+24b]
=(a-2b)^2[8a+24b]
=(-9-6)^2[8*(-9)+24*3)
=(-15)^2[-72+72]
=0

The square of (2a) minus the fourth power of (8a) multiplied by the square of (a + b)
Decomposition factor: the square of (2a) minus the fourth power of (8a) multiplied by the square of (a + b)

Is it (2a) ^ 2 - (8a) ^ 4 * (a + b) ^ 2, or [(2a) ^ 2 - (8a) ^ 4] * (a + b) ^ 2
If the former, the original formula = 4A ^ 2 [1-1024a ^ 2 (a + b) ^ 2] = 4A ^ 2 [1-32a (a + b)] [1 + 32A (a + b)]
=4a^2(1-32a^2-32ab)(1+32a^2+32ab)
If the latter, the original formula = 4A ^ 2 (1-1024a ^ 2) (a + b) ^ 2 = 4A ^ 2 (1-32a) (1 + 32a) (a + b) ^ 2

If a = {the square of X - ax + 3 = 0} and the set a has only one element, we can find the value of A

A = {the square of X | X - ax + 3 = 0} and set a has only one element
Then the square - ax + 3 = 0 of quadratic equation x has two equal real roots
So a & # 178; - 4 × 3 = 0
So a & # 178; = 12
So a = ± 2 √ 3

If there is only one element a in the set a = {x | x ^ 2 + ax + B = x}, find the value of a and B?

There is only one solution to the equation where the square of x plus x (A-1) times of (A-1) plus B equals zero. The left side of the equal sign can be transformed into a complete square formula with zero value. Then the solution is that x equals negative half (A-1) is also equal to a, then a equals 1 / 3, and B equals quarter (A-1) square is also equal to 1 / 9
Answer: a = 1 / 3; b = 1 / 9
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