(A's square + B's Square / AB + 2) / / A's Square - B's Square / A-B, where a = 2B = 1 / 2

(A's square + B's Square / AB + 2) / / A's Square - B's Square / A-B, where a = 2B = 1 / 2

(square of a + square of B / AB + 2) / (square of a - square of B) / (a-b)
=[(a²+b²)/ab+2]÷(a²-b²)/(a-b)
=(a²+2ab+b²)/(ab)÷(a+b)(a-b)/(a-b)
=(a+b)²/(ab)×1/(a+b)
=(a+b)/(ab)
a=2,b=1/2
simple form
=(2+1/2)/(2×1/2）
=5/2

If | a-5 | + 1 / 2B square + B + 1 / 2 = 0, find the value of a and B

|A-5 | + 1 / 2B square + B + 1 / 2 = 0
|a-5|+1/2(b+1)^2=0
a-5=0 b+1=0
a=5 b=-1

Why is the square of a + 2Ab + B equal to the square of (a + b)?

Square of a + 2Ab + square of B
=a^2+ab+ab+b^2
=a(a+b)+b(a+b)
=(a+b)(a+b)
=(a+b)^2

It is proved that a plus B is greater than or equal to 2Ab

The square is greater than or equal to 0
(a-b)²≥0
a²-2ab+b²≥0
a²+b²≥2ab