Solution equation: x2-8x + 12 = 0

Solution equation: x2-8x + 12 = 0

The formula: x2-8x + 42 = - 12 + 42, namely (x-4) 2 = 4, the formula: x-4 = ± 2, the solution: X1 = 6, X2 = 2

Given X & # 178; + Y & # 178; - 8x-10y + 41 = 0, then the value of X / Y-Y / X is

x²+y²-8x-10y+41=0
(x²-8x+16)+(y²-10x+25)=0
(x-4)²+(y-5)²=0
∴x-4=0,y-5=0
∴x=4,y=5
∴x/y-y/x
=4/5-5/4
=16/20-25/20
=-9/20

It is known that: the square of X + the square of Y - 6x + 10Y + 34 = 0, find x + y =?

Divide 34 into 9 and 25 (x ^ 2-6x + 9) + (y ^ 2 + 10Y + 25) = 0
So (x-3) ^ 2 + (y + 5) ^ 2 = 0
If the sum of two nonnegative numbers is zero, then both numbers are zero
So x = 3, y = - 5
X+Y=-2