If 4x-5 and 3x-9 are opposite numbers, then x =?

If 4x-5 and 3x-9 are opposite numbers, then x =?

∵ 4x-5 and 3x-9 are opposite numbers
∴4x－5=－(3x－9)
=>4x－5=－3x＋9
=>7x=4
=>x=4/7

If x is an integer and the value of formula 9-7x + | 19-3x | - | 29-4x |, is constant, the value of X is obtained

When XX > 19 / 3
9-7x+|19-3x|-|29-4x|
=9-7x-（19-3x）-(29-4x)
=-39
When x is 29 / 4
9-7x+19-3x-(29-4x)
=9-7x-（19-3x）+(29-4x)
=19-8x
Since the value of 9-7x + | 19-3x | - | 29-4x |, is constant
So 29 / 4 > x > 19 / 3
And because x is an integer,
So x = 7

When the value range of X is____ The value of formula - 4x + 4-7x - 1-3x + 4 is a constant_____

Ordinary life 999,
Detailed answers are as follows, understand and then adopt, do not understand can hi me!
If we want the value to be a constant, we must find a way to eliminate the variable x. we can find that there are three terms with X, 4x; 7x; 3x,
Because the sign of - 4x is fixed and will not change, we need to make "7x" sign positive and "3x" sign negative, so that the original formula can be changed to the lower form to eliminate X
- 4x + 4-7x - 1-3x + 4
=-4x+(7x-4)-(3x-1)+4
To meet the changes above, we must
4-7x=4/7
1-3x=1/3
Take the intersecting part as x > = 4 / 7, and the value is 1

When the value range of X is______ The value of the formula - 4x + | - 4-7x | - | - 1-3x | + 4 is constant______ ．

Let 4-7x = 0, get x = 47, let 1-3x = 0, get x = 13, when x ≤ 13, 4-7x > 0, 1-3x ≥ 0, - 4x + | 4-7x | - | 1-3x | + 4 = - 4x + 4-7x-1 + 3x + 4 = 7-8x, the formula changes with the change of x, not constant; when 13 < x < 47, 4-7x > 0, 1-3x < 0, - 4x + | 4-7x | - | 1-3x | + 4 = - 4x + 4-7x +