How to convert building area and residential area? How much is the building area converted into residential area? What is the formula?

How to convert building area and residential area? How much is the building area converted into residential area? What is the formula?

I don't know what the concept of residential area is. Let's talk more. Maybe you have something to ask. Building area = built-in building area + shared area. Shared coefficient = shared area △ building area. In high-rise towers, the shared coefficient is usually between 25% and 30%. In high-rise buildings, the shared coefficient is usually between 20% and 25%

Who knows all the formulas of primary school mathematics

1. Number of copies × number of copies = total number
Total number of copies
Total number of copies = number of copies
2.1 times × times = several times
How many times △ 1 times = Times
Several times △ times = 1 times
3 speed × time = distance
Distance △ speed = time
Distance △ time = speed
4 unit price × quantity = total price
Total price / unit price = quantity
Total price △ quantity = unit price
5. Working efficiency × working time = total amount of work
Total workload △ work efficiency = working hours
Total amount of work △ working time = working efficiency
6 addend + addend = sum
Sum - one addend = another addend
7 subtracted - subtracted = difference
Subtracted difference = subtracted
Difference + subtraction = subtracted
8 factor × factor = product
Product △ one factor = another factor
9 divisor / divisor = quotient
Divisor / quotient = divisor
Quotient x divisor = divisor
Primary school mathematics figure calculation formula
1 square
C perimeter s area a side length
Perimeter = side length × 4
C=4a
Area = side length × side length
S=a×a
2 cube
5: Volume a: edge length
Surface area = edge length × edge length × 6
S table = a × a × 6
Volume = edge length × edge length × edge length
V=a×a×a
3 rectangle
C perimeter s area a side length
Perimeter = (length + width) × 2
C=2(a+b)
Area = length × width
S=ab
4 cuboid
5: Volume s: Area A: length B: width H: height
(1) Surface area (L × W + L × H + W × h) × 2
S=2(ab+ah+bh)
(2) Volume = length × width × height
V=abh
5 triangles
S area a bottom h height
Area = bottom × height △ 2
s=ah÷2
Triangle height = area × 2 △ bottom
Triangle bottom = area × 2 △ height
6 parallelogram
S area a bottom h height
Area = bottom × height
s=ah
7 trapezoid
S area a upper bottom B lower bottom h height
Area = (upper bottom + lower bottom) × height △ 2
s=(a+b)× h÷2
8 round
S area C perimeter Π d = diameter r = radius
(1) Perimeter = diameter ×Π = 2 ×Π× radius
C=∏d=2∏r
(2) Area = radius × radius ×Π
9 cylinder
v: Volume H: height s; bottom area R: bottom radius C: bottom perimeter
(1) Side area = perimeter of bottom surface × height
(2) Surface area = side area + bottom area × 2
(3) Volume = bottom area × height
(4) Volume = side area △ 2 × radius
10 cone
v: Volume H: height s; bottom area R: bottom radius
Volume = bottom area × height △ 3
Total number △ total number of copies = average number
The formula of sum difference problem
(sum + difference) △ 2 = large number
(sum difference) △ 2 = decimal
The problem of sum times
Sum (multiple-1) = decimal
Decimals × multiples = large numbers
(or sum - decimal = large)
Differential multiple problem
Difference (multiple-1) = decimal
Decimals × multiples = large numbers
(or decimal + difference = large)
The problem of tree planting
1. The tree planting problem on non closed lines can be divided into the following three cases
(1) if trees are to be planted at both ends of the non closed line, then:
Number of plants = number of segments + 1 = total length △ plant spacing-1
Total length = plant spacing × (number of plants - 1)
Plant spacing = total length (number of plants - 1)
(2) if trees are to be planted at one end of the non closed line and not at the other end, then:
Number of plants = number of segments = total length △ plant spacing
Total length = plant spacing × number of plants
Plant spacing = total length △ number of plants
(3) if trees are not planted at both ends of the non closed line, then:
Number of plants = number of segments-1 = total length △ spacing-1
Total length = plant spacing × (number of plants + 1)
Plant spacing = total length (number of plants + 1)
2. The quantitative relationship of tree planting on closed lines is as follows
Number of plants = number of segments = total length △ plant spacing
Total length = plant spacing × number of plants
Plant spacing = total length △ number of plants
Profit and loss
(profit + loss) △ the difference between the two distributions = the number of shares participating in the distribution
(big profit - small profit) △ the difference between the two distributions = the number of shares participating in the distribution
(big loss - small loss) △ the difference between the two distributions = the number of shares participating in the distribution
Encounter problem
Encounter distance = speed and X encounter time
Encounter time = encounter distance △ speed and
Speed sum = encounter distance △ encounter time
Follow up questions
Pursuit distance = speed difference × pursuit time
Pursuit time = pursuit distance △ speed difference
Speed difference = pursuit distance △ pursuit time
Flow problem
Downstream velocity = hydrostatic velocity + water velocity
Countercurrent velocity = still water velocity - water velocity
Hydrostatic velocity = (downstream velocity + countercurrent velocity) △ 2
Water flow velocity = (downstream velocity countercurrent velocity) △ 2
Concentration problem
Weight of solute + weight of solvent = weight of solution
Weight of solute / weight of solution × 100% = concentration
Weight of solution × concentration = weight of solute
Weight of solute △ concentration = weight of solution
Profit and discount
Profit = selling price cost
Profit margin = profit / cost × 100% = (selling price / cost-1) × 100%
Up and down amount = principal × up and down percentage
Discount = actual selling price △ original selling price × 100% (discount < 1)
Interest = principal × interest rate × time
After tax interest = principal × interest rate × time × (1-20%)

A total of 1035 shakes. How many people participated?

Let the number of handshakes be n, and the number of handshakes be s. n = 2, s = 1, n = 3, s = 3 = 1 + 2, n = 4, s = 6 = 1 + 2 + 3, n = 5, s = 10 = 1 + 2 + 3 + 4, n = 6, s = 15 = 1 + 2 = 3 + 4 + 5. To sum up, when n people shake hands (n ≥ 2), the number of handshakes is s = 1 + 2 + 3 + +(n-1) using the formula of arithmetic sequence, that is s = n (n-1) / 2 when s = 1035 = n (?)