If 3x + 4 = 25, then 4x + 3 equals () A. 31B. 7C. 25

If 3x + 4 = 25, then 4x + 3 equals () A. 31B. 7C. 25

3x + 4 = 25, & nbsp; 3x + 4-4 = 25-4, & nbsp; & nbsp; 3x △ 3 = 21 △ 3, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 7; 4 × 7 + 3, = 28 + 3, = 31, so select: a

If 3x + 4 = 25, then 4x + 3 equals ()
A. 31B. 7C. 25

3x + 4 = 25, & nbsp; 3x + 4-4 = 25-4, & nbsp; & nbsp; 3x △ 3 = 21 △ 3, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 7; 4 × 7 + 3, = 28 + 3, = 31, so select: a

Given that x ^ 4 + 4x ^ 3 + 6px ^ 2 + 4qx + R can be divided by x ^ 3 + 3x ^ 2 + 9x + 3, find the value of P, Q, R

Let x ^ 4 + 4x ^ 3 + 6px ^ 2 + 4qx + r = (x ^ 3 + 3x ^ 2 + 9x + 3) (x + m),
Expand to x ^ 4 + (M + 3) x ^ 3 + (3m + 9) x ^ 2 + (9m + 3) x + 3M,
The comparison coefficients are m + 3 = 4, 3M + 9 = 6p, 9m + 3 = 4q, 3M = R,
The solution is m = 1, P = 2, q = 3, r = 1

If x ^ 4 + 3x ^ 3 + 4x ^ 2 + ax + 11 can be divided by X + 1, try to find a

The designer is a
x^4+3x^3+4x^2+ax+11=A(x+1)
When x = - 1, x + 1 = 0
On the right is 0
So the left side is also 0
So x = - 1
x^4+3x^3+4x^2+ax+11=1-3+4-a+11=0
a=13

It is known that the polynomial 3x3 + AX2 + 3x + 1 can be divided by x2 + 1, and the quotient is 3x + 1, then the value of a is______ ．

From the meaning of the question, we can get 3x3 + AX2 + 3x + 1 = (x2 + 1) (3x + 1), ∧ 3x3 + AX2 + 3x + 1 = 3x3 + x2 + 3x + 1, ∧ a = 1

Solving equation: 3x + 2Y = 5 (1) 4x-3y = 1 (2) (using substitution method)

From 3x + 2Y = 5, we can get x = (5-2y) / 3 (3). By substituting (3) into (2), we can get 4 * (5-2y) / 3 - 3Y = 1. By solving this one variable linear equation, we can get y = 1. By substituting y = 1 into any equation, we can get x = 1

0.5x(4x-3x)=105 //?

4x-3x=105÷0.5
x=210

Who can help me simplify these two algebraic expressions: 90% (200X) + 90% [(4x + 5) X40] and 200X + (3x + 5) X40

The first is 324x + 180, and the second is 320x + 200

3 (X-60) - 20 = (380-x) + 60 3x-200 = 440-x 4x = 640 x = 160

200=180+20
3(x-60)-20=(380-x）+60
3x-180-20=440-x
3x-200=440-x
4x=640
x=160

To solve the linear equations of three variables 1, 3x + 7Y + Z = 150 2, 4x + 10Y + Z = 200

The first-order equation of three variables can only be solved by three relations. Now we can only get x + 3Y = 50 and have countless solutions