If x = - 1y = 2 and x = 2Y = - 1 are two solutions of the equation MX + NY = 10, then M + n = 1___ .

If x = - 1y = 2 and x = 2Y = - 1 are two solutions of the equation MX + NY = 10, then M + n = 1___ .


∵ x = - 1y = 2 and x = 2Y = - 1 are the two solutions of the equation MX + NY = 10, substituting into - M + 2n = 10, ① 2m-n = 10, ② and ① + ② to get: M + n = 20



Solution equation: 2 (X-2) - 3 (4x-1) = 9 (1-x)


Remove brackets: 2x-4-12x + 3 = 9-9x, shift: 2x-12x + 9x = 9 + 4-3, merge similar terms: - x = 10, coefficient 1: x = - 10



I met an equation. Who can help me? 2 {x + 2} - 3 {4x-1} = 9 {1-x}


Original formula = 2x + 4-12x + 3 = 9-x
2X-12X+X=9-4-3
-9X=2
X=-9/2



Using factorization method to solve the equation: 4 times the square of x-4x + 1 = 2 (1-2x)





Factorization cross multiplication 2x + 3x + 1
1、2x^2+3x+1
2、15x^2-2x-1
3、3x^2+4x+1
4、2x^2+7x+5
5、3x^2-7x+4


1.(2x+1)(x+1)
2.(5x+1)(3x-1)
3.(3x+1)(x+1)
4.(2x+5)(x+1)
5.(3x-4)(x-1)



Let's try to decompose the factor by cross multiplication. We know that 2x ^ 2-3x-20 = (2x + 5) (x-4),
Try to factorize polynomial 2 (x ^ 2-3x) ^ 2-3 (x ^ 2-3x) - 20
Quick search


Here a = x ^ 2-3x
Then 2A ^ 2-3a-20
=(2a+5)(a-4)
=[2(x^2-3x)+5](x^2-3x-4)
=(2x^2-6x+5)(x-4)(x+1)



Solve the following equation (cross phase multiplication) (1) x Λ 2-10x + 21 = 0. (2) x Λ 2-3x-10 = 0


(1)x∧2-10x+21=0
(x-3)(x-7(=0
x=3
x=7
(2)x∧2-3x-10=
(x+2)(x-5)=0
x=-2
x=5



On the calculation of cross multiplication decomposition 1. (2x + 1) (3x + 3) 2.2x ^ 2-x-3 3.3b ^ 2 + 14b-5


1. The solution is 6x ^ 2 + 6x + 3x + 3 = 6x ^ 2 + 9x + 3
2. Multiply the cross by 1, 2, 1 - 3 (vertical) to get (x + 1) (2x-3)
3. Multiply the cross by 1 35 - 1 (vertical) to get (x + 5) (3x-1)



Use cross multiplication to calculate the equation: (6x-1) (2x + 5) = (4x-7) (3x + 2),
It should be: (6x-1) (2x-5) = (4x-7) (3x + 2)


After removing the brackets from the original equation
12x²+28x-5=12x²-13x-14
The results are as follows
41x=-9
The solution is x = - 9 / 41



Cross multiplication of X to the second power-7x-8


1 -8
×
1 1
The original formula = (X-8) (x + 1)