In the second semester of the seventh grade, the mathematical equation is quadratic; 2x + 3Y = 7 3x-5y

In the second semester of the seventh grade, the mathematical equation is quadratic; 2x + 3Y = 7 3x-5y

3x-5y =? Without the condition 2x + 3Y = 7 ① 3x-5y = 1 ② ① * 5 + ② * 310x + 15y + 9x15y = 35 + 319x = 38x = 22 * 2 + 3Y = 73y = 7-4y = 1

2x-87+3y=0 5y=3x-7
2x-87+3y=0
5y=3x-7
A system of equations to find the values of X and y

1 type X3 + 2 type x2
So 19y = 247
y=13
2x-87+3*13=0
x=-24

Solving the fractional equation 24 / x + 1 = 20 / X
Solving the fractional equation 24 / x + 1 = 20 / X

24 /（x + 1）= 20 / x
Multiply both sides by X (x + 1) to get:
24 x = 20（x + 1）
24 x = 20 x + 20
4 x = 20
x = 5
Test: when x = 5, X (x + 1) ≠ 0
X = 5 is the solution of the original equation