How to solve (x-40) (240-3x) = 900

(x-40) (240-3x) = 900 (x-40) (80-x) = 30080x-xsquare-3200 + 40x = 300-xsquare + 120x-3500 = 0 method 1: cross multiplication (x-50) (- x + 70) = 0x1 = 50 x2 = 70 method 2: matching method - xsquare + 120x-3600 + 100 = 0 (X-60) quare = 100x-60 = plus minus 10x1 = 50 x2 = 70

How to solve (3x-40) x = 560?

(3x-40) x=560
The original solution: 3x ^ 2-40x-560 = 0, according to the formula x = (- B ± √ (b ^ 2-4ac)) / 2A
(where a is the coefficient of quadratic term, B is the coefficient of linear term, C is the constant term, in your formula, a, B, C are 3, - 40, - 560 respectively)
The solution is x = (20 ± 4 √ 130) / 3

How to solve 3x-5 = x + 5

Move the right x to the left and the left number to the right

How to solve (x-40) (240-3x) = 900