A metal block, put in the liquid with density P1, measure weight G1 with spring scale, put in the liquid with density P2, calculate the liquid density I already know: Suppose the density p and volume V of the metal block p1Vg+G1=pVg p2Vg+G2=pVg Solution V=(G1-G2)/(p1g-p2g) But how to get "P = (g1p2-g2p1) / (g1-g2)" from the formula of V?

There is a piece of metal in physics. When it is called in the liquid with density P1, the indication of the spring dynamometer is G1; when it is called in the liquid with density P2, it is called time
The indication of spring dynamometer is G2, and the density of metal block is calculated

p=(G1p2-G2p1)/(G1-G2)
G1=pVg-p1Vg (1)
G2=pVg-p2vg (2)
(1) (2) the density p of the metal can be obtained by the equation

As shown in the figure on the right, study the pressure inside the liquid with a manometer. If the density of the liquid in the two cups is P1 and P2 respectively, and the two metal rubber films are at the same depth, then
A.P1>P2
B.P1

Pressure P = ρ GH
The information you have provided is incomplete and cannot be concluded
According to the question you give, it is to push down according to the formula
Which cup has the highest liquid density and pressure, provided the same depth
If 1 > 2, choose a
The other two are pushing themselves down

Solve the equation 3x divided by 4 = 6

3x÷4=6
3x △ 4 × 4 = 6 × 4
3x=24
x=8

How to solve the equation 6 (3x-2) = 4 (3x + 3)

6（3x-2)=4(3x+3)
18x-12=12x+3
6x=24
x=4

Solving equation 3x-4 * 6 = 0

3x-24=0
3x=24
x=8

The solution equation is 0.4 × 6 + 3x = 4.8

0.4×6+3x=4.8
2.4 +3x= 4.8
3x= 2.4
x= 0.8
If you don't understand, you can continue to ask this question
Please select it as a satisfactory answer in time,

Solve the equation 3x + 21 = 0
No drawing

3x+21=0
3x=-21
x=-7

Solving equation (3x + 4) (3x-4) = 9 (X-2) ^ 2

（3x+4)(3x-4)=9(x-2)^2
(3x)^2-4^2=9(x^2-4x+4)
9x^2-16=9x^2-36x+36
-16-36=-36x
36x=52
x=13/9

Solving equation x + 2 + 3x-1 = 9

When x ≤ - 2, the original formula becomes:
-x-2-3x+1=9
-4x-1=9
4x=-10
x=-2.5
When - 2

There is a piece of metal in physics. When it is called in the liquid with density P1, the indication of the spring dynamometer is G1; when it is called in the liquid with density P2, it is called time The indication of spring dynamometer is G2, and the density of metal block is calculated

As shown in the figure on the right, study the pressure inside the liquid with a manometer. If the density of the liquid in the two cups is P1 and P2 respectively, and the two metal rubber films are at the same depth, then A.P1>P2 B.P1