Given the complete set u = {x | x2 + 2x-15 > 0}, a = {x | x-4 > 0}, then CUA is

Given the complete set u = {x | x2 + 2x-15 > 0}, a = {x | x-4 > 0}, then CUA is

The complete set u = {x | x2 + 2x-15 > 0},
(x+5) (x-3) >0
X > 3 or x0}
x>4
Then CUA is (- infinity, - 5) U (3, + infinity)

Known complete set u = {0, 1, 2 If (CUA) ∩ (cub) = {0, 4, 5}, a ∩ (cub) = {1, 2, 8}, a ∩ B = {9}, try to find a ∪ B

∵ complete set u = {0, 1, 2 , 9}, (CUA) ∩ (cub) = {0, 4, 5}, a ∩ (cub) = {1, 2, 8}, a ∩ B = {9}, make a Wayne graph, as shown in the right graph, a = {1, 2, 8, 9}, B = {3, 6, 7, 9}, a ∪ B = {1, 2, 3, 6, 7, 8, 9}

Complete set u = {1,2,3,4,5,6,7,8,9}, (CUA) ∪ (cub) = {2,3,4,6,7,8}, (CUA) ∩ B = {3,7}, (CUA) ∪ B = {1,3,5,6,7,8,9}
Find a, B

A={1,2,4,5,9}
B={1,3,5,7,9}

If the complete set u = {1,2,3,4,5,6,7,8,9}, a ∩ B = {2}, CUA ∩ cub = {1,9}, CUA ∩ B = {4,6,8}, then a =?

A={2,3,5,7},

Given the complete set u, set a = {1,3,5,7}, CUA = {2,4,6}, Cub = {1,4.6}, find set B

B={2,3,5,7}

If we know that a and B are subsets of the set u = {13,5,7,9}, and a intersects B = ｜ 3 ｜, (cub) intersects a = ｜ 9 ｜, then a =?

Is your u wrong? Is it u = (1,3,5,7,9)
A=（3,9）

Given the set a = {x 2 power + (B + 2) x + B + 1 = 0} = {a}, find the proper subset of B = {x 2 power + ax + B = 0}

A = {a} so this quadratic equation with one variable has two identical roots x = a, so the equation is (x-a) (x-a) = 0 X & sup2; - 2 ax + A & sup2; = 0 X & sup2; + (B + 2) x + B + 1 = 0, corresponding coefficients are equal - 2A = B + 2A & sup2; = B + 1A & sup2; + 2A = - 1A = - 1, B = 0, so the equation of B is X & sup2; - x = 0 x = 0, x = 1b = {0,1} so

Let a = {x, y} | x squared - y squared divide by 36 = 1}, B = {x, y} | x squared of y = 3}, find the number of subsets of intersection B of A
But one is hyperbola, and the other is exponential function. How can there be eight intersections

There are three intersections between the x-square of x-y-square divided by 36 = 1 and the x-square of y = 3
The number of subsets of a intersecting B = 2 ^ 3 = 8

If the set {(2,3)} is a subset of (a intersection b), a = {(x, y) | ax-y square + B = 0}, B = {(x, y) | x square + PX + 12 = 0}, then a =? B =?
Ah, sorry... There is something wrong with the following question,.
If the set {(2,3)} is a subset of (a intersection b), a = {(x, y) | ax-y square + B = 0}, B = {(x, y) | x square - ay + B = 0}, then a =? B =?

(2,3) substitute 2a-9 + B = 0, 4a-3 + B = 0
A = - 3, B = 15

Given x + y = 10, the third power of X + the third power of y = 280, find the value of X & # 178; + Y & # 178

How: (x + y) we are: (x + y) \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\+ 2Y & # 178; = 562x