Given a & # 178; b = 5, then - AB (cubic power of a, b-2a) = if x power of 0.001 = 1 and Y power of (- 13) = - 1 / 27, then X-Y=

Given a & # 178; b = 5, then - AB (cubic power of a, b-2a) = if x power of 0.001 = 1 and Y power of (- 13) = - 1 / 27, then X-Y=

1. A & # 178; b = 5 multiply both sides of a to get the third power of a, B = 5A
Substituting - AB (5a-2a) = - AB times 3A = - 3A & # B
Replace a & # 178; b = 5 with - 3A & # 178; b = - 3 × 5 = - 15

What is the power of a to the 12th power + 2A + 178; multiplied by a to the 10th power?

The 12th power of a + 2A & # 178; multiplied by the 10th power of a
=a^12+2a^12
=3a^12

If u = {x | x ≥ - 3} and a = {x | x ＞ 1}, then ∁ UA=______ ．

∵ complete set u = {x | x ≥ - 3}, set a = {x | x ＞ 1}, ∁ UA = {x | - 3 ≤ x ≤ 1} = [- 3, 1]

If u = R, a = {x | 1 ≤ x ≤ 3 or 4

CRA = {x | x ＜ 1 or 3 ＜ x ≤ 4 or X ≥ 6} adopted. If you don't understand, continue to ask me

Given the complete set u = R and the set M = {x │ X-1 │ ≤ 2}, we find the complement of M
Trouble will do, teach me

Analysis: from the complete set u = R, set M = {x | X-1 | ≤ 2}, then calculate according to the definition and algorithm of intersection
Because the set M = {x | X-1 | ≤ 2} = {x | - 1 ≤ x ≤ 3}, the complete set u = R,
| cum = {x | x ＜ - 1, or X ＜ 3}
Note: this question examines the complement operation of set and the solution of simple inequality with absolute value
Hope to help you!

Let u = {x | x ∈ n * and X ≤ 10}, and its subset a = {1,2,4,5,9} B = {4,6,7,8,10}, find a ∩ B, a ∪ B

No, I just went to senior one
U={1,2,3,4,5,6,7,8,9,10},
A ∩ B = {4}; a intersects B to find common parts
A ∪ B = {1,2,4,5,6,7,8,9,10}, a and B find the combination of two, do not write the three which do not have two, and the maximum cannot be larger than the complete

Given the complete set s = (12345678) a = (2356), B = (1357), find (CSA) U (CSB), CS (a intersection b), and judge according to the result
2. Find (CSA) intersection (CSB), CS (a) intersection (b), and judge the relationship between (CSA) intersection (CSB) and CS (AUB) according to the results

（CsA)U(CsB)=(1、2、4、6、7、8）
CS (a, b) = (3, 5)
The relationship between (CSA) intersection (CSB) and CS (AUB): the union of (CSA) intersection (CSB) and CS (AUB) is s

Let s have two subsets A and B. if x ∈ CSA {x ∈ B, then x ∈ A is x ∈ CSB______ Conditions

⊆ a complete set s has two subsets A and B, if x ∈ CSA {x ∈ B, ⊆ CSA ⊆ B, take the complement on both sides, ⊇ cscsa ⊇ CSB, cscsa = a ⊇ a ⊇ CSB, if x ∈ CSB, we can get that x ∈ a, ⊇ x ∈ sb {x ∈ a, ⊇ x ∈ a are necessary and not sufficient conditions for X ∈ sb, so the answer is: necessary and not sufficient

It is known that the complete set u is R and the set a = {x | 0

（1）(1,2) (2) [-3,0] (3) (-3,0)

Let s = R, a = a {x | x ≥ - 2}, B = {x | 0 ≤ x}

（1）{x|0≤x