1. M = {Y / y = x & # 178; - 2x-1}, n = {Y / y = x & # 178; + 2x + 3}, find the intersection of M and n 2. M = {(x, y) / y = x}, n = {(x, y) / y = 2x-1}, find the intersection of M and n 3. M = {X / y = radical (X-2)}, n = {X / y = one part of radical (3-x)}, find the intersection of M and n

1. M = {Y / y = x & # 178; - 2x-1}, n = {Y / y = x & # 178; + 2x + 3}, find the intersection of M and n 2. M = {(x, y) / y = x}, n = {(x, y) / y = 2x-1}, find the intersection of M and n 3. M = {X / y = radical (X-2)}, n = {X / y = one part of radical (3-x)}, find the intersection of M and n

First question:
Y = x2-2x-1 = (x-1) 2 - 2, so the range of Y is [- 2, + infinity)
Y = x2 + 2x + 3 = (x + 1) 2 + 2, so the range of Y is [2, + infinity]
Intersection: [2, + infinity]
Second question
That is to say, the intersection of these two lines, the simultaneous equations y = x and y = 2x-1, get x = 1, y = 1
The intersection is (1,1)
The third question
The number in the root sign must be ≥ 0 and the denominator must not be 0
So X-2 ≥ 0, X ≥ 2
3-x ＞ 0 (denominator cannot be 0) x ＜ 3
The intersection is [2,3]

Given a = {y | y = - x2 + 2x-1}, B = {y | y = 2x + 1}, then a ∩ B=______ (expressed in intervals)

According to the meaning of the question, for a, y = - x2 + 2x-1 = - (x2-2x + 1) = - (x-1) 2 ≤ 0, then a = {y | y = - x2 + 2x-1} = {y | y ≤ 0}, B = {y | y = 2x + 1} = R, then a ∩ B = {y | y ≤ 0} = (- ∞, 0]; so the answer is (- ∞, 0]

How to calculate 3x + 2Y = 36 = 5x + 2Y = 72?

3x+2y=36 【1】
5x+2y=72 【2】
【2】 - [1] is 2x = 36, x = 18
Substitute [1] to get y = - 9

Solving inequality system: 3 / 2x + 5-1 > 2-x 2x + 3 ≤ x + 11
-I don't have too many reward points. I'll make it up later
2-x 2x + 3, 2-x 2x + 3 ≤ x + 11, and then take the intersection of the two ranges (for example, x > 1, x > 3, the result is: x > 3)

Find the two formulas respectively, and then take the intersection of the two ranges (for example, x > 1, x > 3, the result is: x > 3)

Even solutions of inequality system 11-2 (x-3) ≥ 3 (x-1) X-2 > 1-2x|3

Because: 11-2 (x-3) ≥ 3 (x-1)
So: 4 ≥ x,
Because: X-2 > 1-2x|3,
So: x > 1
So: 4 ≥ x > 1
Because: even solution
So: x = 2 or 4

Find the even solutions of the system of inequalities 11 − 2 (x − 3) ≥ 3 (x − 1) x − 2 ＞ 1 − 2x3

From the solution of Formula 1, we can get x ≤ 4. From the solution of formula 2, we can get that the solution set of the inequality system of X ＞ 75 is 75 ＜ x ≤ 4, and the even number solution of the inequality system is x = 2,4

11-2 (x-3) ≥ 3 (x + 1) and X-2 ≥ 3 / 1-2x solving inequality systems

11-2(x-3)≥3(x+1)
11-2x+6≥3x+3
14≥5x
x≤14/5
x-2≥3/(1-2x)
(x-2)-3/(1-2x)≥0
(x-2)+3/(2x-1)≥0
(2x²-x-4x+2+3)/(2x-1)≥0
(2x²-5x+5)/(2x-1)≥0
For 2x & # 178; - 5x + 5
Δ=25-40=-150
2x-1>0
x>1/2
To sum up, 1 / 2

How to solve the inequality 2x ^ 2-x + 1 divided by 2x + 1 > 0?

It is easy to know that no matter x takes any real number 2x ^ 2-x + 1 > 0, so when 2x + 1 > 0 is x > - 1 / 2, 2x ^ 2-x + 1 / 2x + 1 > 0, the solution is x > - 1 / 2

Solution inequality: 6 (2x-1) ≥ 10x + 1, I really won't, thank you for the process Oh, thank you

6(2x-1)≥10x+1
12x-6≥10x+1
12x-10x≥1+6
2x≥7
x≥7/2

Solving inequality - (x + 1) > 3.2X + 9 > 3

-（x+1）＞3
→ -x-1＞3
→ - x > 4 / / move item
→ x < - 4 / / divided by negative number - 1, the direction of unequal sign changes
2x+9＞3
→ 2x > - 6 / / move items
→ x > - 3 / / divided by positive number 2, the direction of inequality sign remains unchanged