Given that the solution set of inequality system {2x-3a 〈 7d and 6a-3x 〈 5A is 5 〈 x 〈 22, find the value of a and D

Given that the solution set of inequality system {2x-3a 〈 7d and 6a-3x 〈 5A is 5 〈 x 〈 22, find the value of a and D

The result of solving inequality system is: A / 3

The square of (3a + 4), (7b + 3x), (5a + 3b), (6a-2b)

The square of (3a + 4)
=9a²+24a+16
The square of (7b + 3x)
=49b²+42bx+9x²
The square of (5a + 3b)
=25a²+30ab+9b²
The square of (6a-2b)
=36a²-24ab+4b²

The solution set of inequality 3x ≥ - 6 is expressed as ()
A. B. C. D.

Solution: 3x ≥ - 6, X ≥ - 2

If the nonnegative integer solution of inequality - 3x + 6 > A is 0,1,2, find the integer a =

x

Inequality x-7-1 of 2

x-7-2＜3x-6;
2x＞-3;
x＞-3/2；
Only one; - 1;
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Solve the inequality about X: X / x ^ 2-8x + 15 > 2

X/(X^2-8X+15)>2
X/(X^2-8X+15)-2>0
(2x2-7x+30)/(x-3)(x-5)>0
Because y = 2x2-7x + 30
∆0
(x-3)(x-5)>0
So X5

Solving inequality X / (X & # 178; - 8x + 15) ≥ 2

Solving inequality X / (x ^ 2-8x + 15) 2

x/(x²-8x+15)-2≥0
(x-2x²+16x-30)/(x^2-8x+15)≥0
(2x²-17x+30)/(x²-8x+15)≤0
That is, (2x & sup2; - 17x + 30) (X & sup2; - 8x + 15) ≤ 0
(2x-5)(x-6)(x-3)(x-5)≤0
Zero is 5 / 2, 3, 5, 6
So it's the needling method
5/2≤x≤3,5≤x≤6
The denominator is not equal to 0
So 5 / 2 ≤ x

X / X & # 178; - 8x + 15 ＞ 2 solution inequality,

It's X / (x-178; - 8x + 15) > 2
x/(x²－8x＋15) >2
x/(x²－8x＋15) -2 >0
General division
(-2x² + 17x -30)/(x²－8x＋15) >0
Both sides at the same time x denominator & #178;
Factorization again
-(2x-5)(x-6)(x-3)(x-5) > 0
I solved this problem in the way of graph
5/2

The integer solution of inequality system {2x-7 ＜ 5-2x x + 1 ＞ 3 / 2 + X is

{2x-7＜5-2x①
{x + 1 ＞ 3 / 2 + x 2
The solution is x < 3
Solution 2 gives x > 1
The solution set of this inequality system is 1 < x < 3
The integer solution of inequality system is 2