Let X1 and X2 be two real roots of the quadratic equation x & sup2; + x = n-2 = MX with respect to x, and let X12 B.M > 1, n Is X & sup2; + X + n-2 = MX

Let X1 and X2 be two real roots of the quadratic equation x & sup2; + x = n-2 = MX with respect to x, and let X12 B.M > 1, n Is X & sup2; + X + n-2 = MX

It is known that the univariate quadratic equation x2 + MX + n = 0 has a root n, then the value of M + n is n

According to Vader's theorem
x1+n=-m
x1n=n
So X1 = - M-N = 1
m+n=-1

The equation of curve C: X & # 178; + Y & # 178; + 2x = 0 with respect to the symmetric curve C1 of straight line y = X-1 is----
I hope you can help me. I'm sick at home. I lost my exercise book. I hope you can help me

I will help you to answer, remember to choose as a satisfactory answer
From y = X-1 we get x = y + 1,
Therefore, replacing x with y + 1 and y with X-1 in the original equation is the equation of C1,
That is, (y + 1) ^ 2 + (x-1) ^ 2 + 2 (y + 1) = 0,
It is reduced to x ^ 2 + y ^ 2-2x + 4Y + 4 = 0

The equation of x ^ 2-y ^ 2-2x + Y-3 = 0 with respect to the axisymmetric figure of line x = 0 is

Let (x, y) be any point of an axisymmetric graph and symmetric with respect to x = 0, then (- x, y) is substituted into the original graph
(- x) ^ 2-y ^ 2-2 (- x) + Y-3 = 0, that is: x ^ 2-y ^ 2 + 2x + Y-3 = 0