If the curve represented by the equation AX & # 178; - XY + Y & # 178; = 4 passes through the point (2,16), then a=

If the curve represented by the equation AX & # 178; - XY + Y & # 178; = 4 passes through the point (2,16), then a=

Substituting the point into the equation, 4a-32 + 256 = 4
We get 4A = - 220
a=-55

Given that the curve represented by the equation AX & # 178; - XY + Y & # 178; = 4 passes through the point (2,16), then a=
If the inclination angle of the straight line is known to be 45 degrees, then the slope K=
If the inclination angle of a straight line is 135 degrees, the slope k is zero=
If a straight line passes through points a (- 2,0) and B (- 5,3), then the slope K=__ , tilt angle a=
If a straight line passes through points a (1,2) and B (3,4), then the slope k=__ , tilt angle a=

Given that the curve represented by equation AX & # 178; - XY + Y & # 178; = 4 passes through points (2,16), then a = - 52, given that the inclination angle of the straight line is 45 degrees, then the slope k = 1, given that the inclination angle of the straight line is 135 degrees, then the slope k = - 1, given that the straight line passes through points a (- 2,0), B (- 5,3), then the slope K=_ -1_ The inclination angle a = 135 ° is known

Find the square of the curve y = x at point (2,

Solution: let the point oblique equation Y-1 = K (X-2) (k is the slope), that is, kx-y-2k + 1 = 0, then kx-x ^ 2-2k + 1 = 0 x ^ 2-kx + 2k-1 = 0, Δ = k ^ 2-4 (2k-1) = k ^ 2-8k + 4 = 0, and the solution is k = 4 ± 2 √ 3. The linear equation is Y-1 = (4 ± 2 √ 3) (X-2)