The perimeter of a rectangle is 4A + 3b, one side is 2A + B-1, and the other side is 2A + B-1? 5(x-y)+3(x-y)-7(x-y)

The perimeter of a rectangle is 4A + 3b, one side is 2A + B-1, and the other side is 2A + B-1? 5(x-y)+3(x-y)-7(x-y)

（4a+3b）÷2-（2a+b-1）
=2a+1.5b -2a-b+1
=0.5b+1

If the perimeter of a rectangle is 4a-b and one side is 2a-b, the other side is 2a-b______ ．

The other side is 12 [(4a-b) - 2 (2a-b)] = 12 (4a-b-4a + 2b) = 12b

The length of a rectangle is (4a-b) cm, and its width is (a-2b) cm less than its length?

Perimeter = (L + W) * 2
So perimeter
Width 4a-b - (a-2b)
4a-b-a+2b
=3a+b
So perimeter (4a-b + 3A + b) * 2
=7a*2
=14a