If G (x) = 1-2x, f [g (x)] = 1-xsquare of X (x is not equal to 0), find f (1 / 2)

If G (x) = 1-2x, f [g (x)] = 1-xsquare of X (x is not equal to 0), find f (1 / 2)


Let g (x) = 1-2x = 1 / 2, then x = 1 / 4
f[g(x)]=(1-x^2)/x^2
Therefore, f (1 / 2) = (1-1 / 16) / (1 / 16) = 15