Given the function f (x) = x & # 178; + 2, then f [f (- 1)] equals ()? Given the function f (x) = x & # 178; + 2, then f [f (- 1)] equals () A、9 B、10 C、11 D、12 Given the function f (x) = (x + 1 (x ≤ 0), 2x-1 (x > 0)) piecewise function, then the abscissa of the intersection of F (x) and X axis is?

Given the function f (x) = x & # 178; + 2, then f [f (- 1)] equals ()? Given the function f (x) = x & # 178; + 2, then f [f (- 1)] equals () A、9 B、10 C、11 D、12 Given the function f (x) = (x + 1 (x ≤ 0), 2x-1 (x > 0)) piecewise function, then the abscissa of the intersection of F (x) and X axis is?

1) f(-1)=3
f[f(-1)]=f(3)=11
So c
2) f(x)=0
The solution is x = - 1, or x = 1 / 2
So the abscissa of the intersection of F (x) and X axis is - 1 or 1 / 2

Given the function f (x) = x2 + 1, x < 0, if f (x) = 10, then x=______ ．

∵ function f (x) = x2 + 1, X ＜ 0, from F (x) = 10, we get x2 + 1 = 10, that is, X2 = 9, that is, x = - 3

Given the function f (x) = x + 1 / X-1, what is f (- x) equal to?

F (x) = x + 1 / X-1, then f (- x) is equivalent to replacing all x in the original formula with - x, that is, f (- x) = - x + 1 / (- x) - 1