If f (1-cosx) = sin ^ x, what is f (3 / 2) equal to
Let 1-cosx = 3 / 2
cosx=-1/2
sin²x+=1-cos²x=3/4
So f (3 / 2) = 3 / 4
If f (x) = sin α - cosx, then f ′ (α)=______ .
F '(x) = SiNx, so f' (α) = sin α, so the answer is sin α
Let f (x) = sin (cosx), (0 less than or equal to x less than or equal to pie), find the maximum and minimum value of F (x)
I'm going to be a little brother. Thank you
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