When the value of independent variable x satisfies what conditions, the value of function y = 3 / 2x + 6 satisfies the following conditions. Y = 0 y < 0 Y > 0 y < 2 When the value of independent variable x satisfies what conditions, the value of function y = 3 / 2x + 6 satisfies the following conditions y=0 y＜0 y＞0 y＜2

When the value of independent variable x satisfies what conditions, the value of function y = 3 / 2x + 6 satisfies the following conditions. Y = 0 y < 0 Y > 0 y < 2 When the value of independent variable x satisfies what conditions, the value of function y = 3 / 2x + 6 satisfies the following conditions y=0 y＜0 y＞0 y＜2

y=3/2x+6
If y = 0, then 3 / 2x + 6 = 0, 3 / 2x = - 6, x = - 4
If y < 0, then 3 / 2x + 6 - 6, x > - 4
If y < 2, then 3 / 2x + 6

Given y = 2x + 1, when x = - 1, the function y = how much; when y = - 2, the independent variable x = how much

Y = 2x + 1, when x = - 1
Y=-2+1
Y=-1
Y = 2x + 1, when y = - 2
-2=2X+1
2X=-3
X=-3/2

Given the function y = - 2x + 3, when the independent variable x increases by 1, the function value Y ()
A. Increase 1b. Decrease 1C. Increase 2D. Decrease 2

Let x = a, then y = - 2A + 3; let x = a + 1, then y = - 2 (a + 1) + 3 = - 2A + 1, so y decreases by 2