（2/5mn^3-m^2n^2+1/6n^4)/(2/3n^2)=?

（2/5mn^3-m^2n^2+1/6n^4)/(2/3n^2)=?

（2/5mn^3-m^2n^2+1/6n^4)/(2/3n^2)
=2/5mn³÷2/3n²-m²n²÷2/3n²+1/6n^4÷2/3n²
=3/5mn-3/2m²-1/4n²

When a 5N force is decomposed into two components, the size of the component is impossible ()
A. They are all 5nb. They are 1000N and 996nc respectively. One component can be 5 × 104nd. One component can be 0.1N and the other is 4N

A. The resultant force range of 5 & nbsp; N and 5 & nbsp; n is 0n ≤ f ≤ 10N, so it may be that 5N is decomposed into two forces, so a is correct; the resultant force range of B, 1000N and 996 & nbsp; n is 4N ≤ f ≤ 1996n, so it may be that 5N is decomposed into two forces, so B is correct; the resultant force range of C, 5 × 104n and 5 × 104n is correct

A force of 10N is decomposed into two components. If one component is known to be 15N, the other component may be ()
A. 10NB. 15NC. 30ND. 40N

The resultant force of two common forces is 10N. If one of them is 15N, the other component force should be 5N ≤ f ≤ 25N, so it may be ab or CD error