If a natural number is divided by 247 to make 63, and by 248 to make 63, what is the remainder of a natural number divided by 26?

If a natural number is divided by 247 to make 63, and by 248 to make 63, what is the remainder of a natural number divided by 26?

When a natural number is divided by 247, the remainder is 63, and when it is divided by 248, the new number obtained by subtracting 63 from this number can be divided by 247 or 248, two adjacent integers are coprime, the new number can be divided by 247 × 248, 247 × 24826 = 6125626 = 2356, and the remainder of this number divided by 26 is equal to the remainder of 63 divided by 26, 6326 = 2 11. Answer: the remainder of natural number divided by 26 is 11

If a natural number is divided by 247 to make 63, and by 248 to make 63, what is the remainder of a natural number divided by 26?

When a natural number is divided by 247, the remainder is 63, and when it is divided by 248, the remainder is 63. The new number obtained by subtracting 63 from this number can be divided by 247 or 248. Two adjacent integers are coprime. The new number can be divided by 247 × 248, 247 × 24826 = 6125626 = 2356. The remainder of this number divided by 26 is 63 divided by 26

If a natural number is divided by 247 to make 63, and by 248 to make 63, what is the remainder of a natural number divided by 26?

When a natural number is divided by 247, the remainder is 63, and when it is divided by 248, the new number obtained by subtracting 63 from this number can be divided by 247 or 248, two adjacent integers are coprime, the new number can be divided by 247 × 248, 247 × 24826 = 6125626 = 2356, and the remainder of this number divided by 26 is equal to the remainder of 63 divided by 26, 6326 = 2 11. Answer: the remainder of natural number divided by 26 is 11