If a natural number is divided by 427 into 63 and 248 into 63, what is the remainder of the natural number divided by 26

If a natural number is divided by 427 into 63 and 248 into 63, what is the remainder of the natural number divided by 26

If a natural number is divided by 427 into 63 and 248 into 63, what is the remainder of the natural number divided by 26
If you subtract 63 from this number, you can divide it by 427 and 248
The least common multiple of 427 and 248 is 427 * 248 = 105896
So this number is: 105896 + 63 = 105959
105959/26=4075.9
That is, the remainder is 9

The product of four continuous natural numbers is 3024, and the average of the four natural numbers is 3024______ ．

The quality factor of 3024 decomposition: 3024 = 2 × 2 × 2 × 3 × 3 × 3 × 7; 2 × 3 = 6; 3 × 3 = 9; 2 × 2 × 2 = 8; that is 3024 = 6 × 7 × 8 × 9, the four natural numbers are 6, 7, 8, 9. The average of the four natural numbers is: (6 + 7 + 8 + 9) △ 4 = 7.5. A: the average of the four natural numbers is 7.5

There are four continuous natural numbers. Their product is 5040. What are the four numbers?
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7、8、9、10