If {an} is an arithmetic sequence with tolerance 1, then {a2n-1 + 2a2n} is () A. Isochromatic sequence with tolerance 3 B. isochromatic sequence with tolerance 4 C. isochromatic sequence with tolerance 6 D. isochromatic sequence with tolerance 9

If {an} is an arithmetic sequence with tolerance 1, then {a2n-1 + 2a2n} is () A. Isochromatic sequence with tolerance 3 B. isochromatic sequence with tolerance 4 C. isochromatic sequence with tolerance 6 D. isochromatic sequence with tolerance 9

Let the tolerance of {an} be D, then d = 1, CN = a2n-1 + 2a2n, then CN + 1 = A2N + 1 + 2a2n + 2, CN + 1-cn = A2N + 1 + 2a2n + 2-a2n-1-2a2n = 6D = 6, so C

Insert 7 numbers between 8 and 40, so that they are equal to the two numbers. What is the tolerance of the equal difference sequence?
emergency

If 7 numbers are inserted, there are 9 numbers in total, and the difference between the maximum number and the minimum number (7 + 1) = 8 tolerances
（40－8）÷（7+1）
＝32÷8
＝4

General term formula of arithmetic sequence-2n + 7 = an to find the first term and tolerance

a1=-2*1+7=5
a(n+1)-an=-2*(n+1)+7-(-2n+7)=-2