Given that the plane passes through two points a (1,2, - 1) and (- 5,2,7) and is parallel to the X axis, its equation is solved

Given that the plane passes through two points a (1,2, - 1) and (- 5,2,7) and is parallel to the X axis, its equation is solved

The plane equation is ax + by + CZ + D = 0;
Because it is parallel to the X axis, a = 0;
The equation becomes: by + CZ + D = 0;
If B = 0, B is not equal to 0 if the parameter is not consistent, and the two sides are divided by B to get the equation deformation as follows:
Y + C / b * Z + D / b = 0
y+Ez+F=0;
Two results are obtained: Y-2 = 0;

Parallel to the ox axis and passing through two points (4.0. - 2) and (5.1.7), the plane equation is solved

The direction vector on the x-axis is V1 = (1,0,0), and the plane passes through P (4,0, - 2), q (5,1,7), so PQ = (1,1,9), so the normal vector of the plane is n = V1 × PQ = (0, - 9,1), so the plane equation is - 9 (y-0) + (Z + 2) = 0, and 9y-z-2 = 0

The plane equation passing through point (0,0,1) and parallel to plane 3x + 4Y + 2Z = 1 is?

The normal vector of the plane is (3,4,2)
Let the coordinates of any point a of the required plane be (x, y, z), and the line connecting with the point (0, 0, 1) be perpendicular to the normal, that is
3 (x-0) + 4 (y-0) + 2 (Z-1) = 0
3x+4y+2z=2

The equation of X can be solved as a non-zero integer k x-4x = 0

Solution (K-4) x = 0
k-4=0
k=4

The solution of the equation kx-k = 2x-5 of X is an integer, and the integer k is obtained

The solution of the equation kx-k = 2x-5 of X is an integer, and the integer k is obtained
kx-k=2x-5
(k-2 )x = k-5
x = (k-5) / (k-2)
= ( k-2 -3) / (k-2 )
= 1 - 3 / (k-2)
So K-2 is 3 or 1 or - 3 or - 1
K = 5 or 3 or - 1 or 1

If the solution of the equation 9x-17 = KX about X is a positive integer, then the value of integer k is ()
A. 8B. 2C. 6，-10D. ±8

If (9-k) x = 17, the solution is x = 179 − K, ∵ x is a positive integer, ∵ 9-k = 1 or 17, the solution is k = 8 or - 8, so choose D

Given that the solution of equation 1 / 4x-5k = 2 about X is x = 2008, then K=

1/4*2008-5K=2
502-5K=2
5K=502-2=500
K=100

Given that x = 2 is the solution of equation 1 / 2 (X-6) = 5K + 12x, find the solution of equation KY = K (1-2y) - 2 about y?

Substituting x = 2 into 1 / 2 (X-6) = 5K + 12x, we get
1/2*(-4)=5k+12*2
k=-26/5
Substituting k = - 26 / 5 into KY = K (1-2y) - 2, we get
-26/5y=-26/5(1-2y)-2
y=8/13

The formula of arithmetic square root of product

(AB) = √ a × √ B (a ≥ 0 and B ≥ 0)

What is the arithmetic square root formula of quotient?
It's urgent

√(a/b)
When a ≥ 0, b > 0
Then √ (A / b) = √ A / √ B
When a ≤ 0, B < 0
Then √ (A / b) = √ (- a) / √ (- b)