Let the solution set of inequality x2-2ax + A + 2 ≤ 0 be m. if M ⊆ [1,4], then the range of real number a is______ ．

Let the solution set of inequality x2-2ax + A + 2 ≤ 0 be m. if M ⊆ [1,4], then the range of real number a is______ ．

The solution set of ∵ inequality x2-2ax + A + 2 ≤ 0 is m, m ⊆ [1,4]. When m = ∞, △ = (- 2A) 2-4 (a + 2) < 0, the solution is, - 1 < a < 2; when m ≠, Let f (x) = x2-2ax + A + 2, the image is a parabola, the opening is upward, and the axis of symmetry is x = a; ■ (− 2a) 2 − 4 (a + 2) ≥ 01 ≤ a ≤ 4f (1) ≥ 0f (4)

In the original algorithm of rational number, we define the new budget "⊕" as follows: when a ≥ B, a ⊕ B = B & # 178;; when a < B, a ⊕ B = a
Then: please use this definition to calculate: 1 ⊕ - 2 ⊕ 5-4 × [(- 3)] ⊕ 2

There are definitions:
1♁（-2）=(-2)²=4,4×【（-3）】=(-3)²=9
Then:
1♁（-2）♁5=4♁5=4,-4×【（-3）】♁2=9♁2=2²=4
So:
1♁（-2）♁5-4×【（-3）】♁2=4-4=0

AB is a rational number. If an operation "♁" is specified and a ♁ B = the square of a-Ab + A-1 is defined, please calculate 3 according to the meaning of ♁
AB is a rational number. If an operation "♁" is specified and a ♁ B = the square of a-Ab + A-1 is defined, please calculate 3 ♁ 6 (1 ♁ 3) ♁ - 3 according to the meaning of ♁