Given that x = 5 is the solution of the equation AX-8 = 20 + a about X, find a The sum of two numbers B is 100 and the difference is 50

Given that x = 5 is the solution of the equation AX-8 = 20 + a about X, find a The sum of two numbers B is 100 and the difference is 50


X = 5 is the solution of the equation AX-8 = 20 + a about X
5a-8=20+a
5a-a=20+8
4a=28
a=7
Let a be X
x-(100-x)=50
x-100+x=50
2x=150
x=75
100-x=25
The number a is 75 and the number B is 25