Solving equations 4x ^ 2 / (1 + 4x ^ 2) = y, 4Y ^ 2 / (1 + 4Y ^ 2) = Z, 4Z ^ 2 / (1 + 4Z ^ 2) = x It's tonight

Solving equations 4x ^ 2 / (1 + 4x ^ 2) = y, 4Y ^ 2 / (1 + 4Y ^ 2) = Z, 4Z ^ 2 / (1 + 4Z ^ 2) = x It's tonight

Two sets of solutions are obtained
0,0,0
0.2119268995,0.2119268995,0.2119268995

It is known that the system of equations 2x + my = 4x + 4Y = 8 about X and y has integer solution, so we can find the value of positive integer M

4x+2my=16 (1)
4x+4y=8 (2)
(1) - (2), got it
2my-4y=8
(m-2)y=4
y=4/(m-2)
Since y is an integer, then m-2 = ± 1, ± 2, ± 4
m=3,4,6 ,1,0,-2
When m = 3, y = 4, x = - 2
When m = 4, y = 2, x = 0
When m = 6, y = 1, x = 1
When m = 1, y = - 4, x = 6
All of them meet the theme
So the positive integer m = 1,4 or 6

It is correct to solve the equations 4x square - y square = 0 x square - XY + 4 = 0

4X & # 178; - Y & # 178; = 0 (1) x & # 178; - XY + 4 = 0 (2) from (1): y = 2x or y = - 2x, substitute the results into (2): 1. X & # 178; - 2x & # 178; + 4 = 0, get x = 2 or x = - 22. X & # 178; + 2x & # 178; + 4 = 0, there is no solution, so x = 2, y = 4 or y = - 4x = - 2, y = - 4 or y = 4, the answers should be written clearly, otherwise, there is no difference