As shown in the figure, a 6m long aluminum alloy strip is used to make a "day" shaped window frame. When the width and height are respectively, the light transmission area of the window is 1.5m2 (excluding the width of the aluminum alloy strip)?

As shown in the figure, a 6m long aluminum alloy strip is used to make a "day" shaped window frame. When the width and height are respectively, the light transmission area of the window is 1.5m2 (excluding the width of the aluminum alloy strip)?

Suppose the width is XM, then the height is 6 − 3x2m. From the meaning of the title, we get: X × 6 − 3x2 = 1.5, the solution is: X1 = x2 = 1, and the height is 6 − 32 = 1.5 (m). Answer: the width is 1m, and the height is 1.5m

In aluminum alloy window engineering, 50 series, 70 series and 50 / 70 are generally distinguished. Which part is the size? The thickness of window frame or the width of center pillar?

The numbers in series 50 and 70 refer to the thickness of the window frame
The center pillar can also be said to be a frame (it can be understood as a frame with glass on both sides), so this dimension can also be obtained by measuring the thickness of the center pillar

How to calculate 20-4.57 + 6.85?

20-4.57+6.85
=20-4+6+0.85-0.57
=22+0.28
=22.28