In 1-2000, there are several numbers that are divided by 3,5,7 to make 1
The number that meets the requirements of the title is the common multiple of 3,5,7 plus 1
The least common multiple of 3,5,7 is 3x5x7 = 105
2000/105=19.5
So in 1-2000, there are 19 numbers that are divided by 3, 5, 7 to 1
0.1 0.2 0.3 0.4 0.5 = 0, punctuate the middle of each number
0.1*(0.2-0.3-0.4+0.5)=0
1.1.3.4.5.6.7 how to add punctuation between these numbers
6×7+3×4×5-1-1