In a section of double track railway, two trains pass at the same time, one speed is 20 meters per second, one speed is 24 meters per second, and the length of the train is 180 meters and 160 meters respectively On a section of double track railway, two trains pass by at the same time. The speed of one train is 20 meters per second, the speed of one train is 24 meters per second, and the length of two trains is 180 meters and 160 meters respectively

In a section of double track railway, two trains pass at the same time, one speed is 20 meters per second, one speed is 24 meters per second, and the length of the train is 180 meters and 160 meters respectively On a section of double track railway, two trains pass by at the same time. The speed of one train is 20 meters per second, the speed of one train is 24 meters per second, and the length of two trains is 180 meters and 160 meters respectively

It takes the same time for two cars to stagger. Let t be set. Suppose a doesn't move, then the speed of B relative to a is 44m / s. The total length of two cars is 340m, so t = 340 / 44 = 7.7s
It should be like this!

There are two trains on a section of double track railway. The speed of train a is 25 / s and that of train B is 30 m / s. The total length of train a is 240 m and that of train B is 200 m
How long does it take for two trains to meet and leave each other?

The total speed of train a and B is set to be 240 meters, the distance between train a and train B is set to be 25 meters, and the distance between train a and train B is set to be 30 meters

2. The two trains are 240 meters long. If the two trains run in opposite directions, it takes 16 seconds from the front to the rear. If the two trains run in the same direction, then
2. The two trains of a and B are 240 meters long. If the two trains run in opposite directions, it takes 16 seconds from the front to the rear. If the two trains run in the same direction, it takes 60 seconds from the rear of a to the front of B. assuming that the speed of a and B is constant, the speed of a and B is calculated

It's up to you
Let a train (express train) be x meters per second and B train (slow train) be y meters per second
(1) Formula: 16x + 16y = 240 × 2 = 480
(2) Formula: 60x-60y = 240
(1) Equation (3) is 240x + 240y = 7200
(2) Equation (4): 240x-240y = 960
(3) Equation + (4): 480x = 8160, x = 17
(3) Equation (4): 480y = 6240, y = 13
A: car a is 17 meters per second, car B is 13 meters per second
Good luck and goodbye