3 by 1 / 4 + 4 by 1 / 5 + 5 by 1 / 6 +. + 99 by 1 / 100= meeting

3 by 1 / 4 + 4 by 1 / 5 + 5 by 1 / 6 +. + 99 by 1 / 100= meeting

3 times 1 / 4 = [(1 / 3) - (1 / 4)]; 4 times 1 / 5 = [(1 / 4) - (1 / 5)]; 5 times 1 / 6 = [(1 / 5) - (1 / 6)];. 99 times 1 / 100 = [(1 / 99) - (1 / 100)], so 3 times 1 / 4 + 4 times 1 / 5 + 5 times 1 / 6 +. + 99 times 1 / 100 = [(1 / 3) - (1 / 4)] + [(1 / 4) - (1 / 5)] + [(1 / 5) - (1 / 6)] + [(1 / 6)]

Two by four by eight By one in 100 by three by five Who is bigger by 99 or 1 / 10
Right, additional reasons

Let a = 1 * 3 * 5 * --- * 99 / 2 * 4 * 6 * --- * 100 = 1 / 2 * 3 / 4 * 5 * 6 * --- * 99 / 100
B=2/3*4/5*6/7*-----*100/101
B>A
A*B=1*2*3*----*100/2*3*4*----101=1/101

Can the simple calculation of 1.76 + (7.4 + 2.6) △ 25 be simple? And (5.01-0.69) △ 12 △ 18

1.76+(7.4+2.6)÷25
=1.76+10÷25
=1.76+0.4
=2.16
(5.01-0.69)÷12÷18
=4.32÷12÷18
=0.36×12÷12÷18
=0.02×18÷18
=0.02

5 + 7 + 9 + 11. + 69 (simple calculation)

5+7+9+11.+69=(5+69)+(7+67)+.(35+39)+37=16x74+37=1221