The diameter of a bacterium is 0.000 015 meters. How many meters can be counted by scientific counting

The diameter of a bacterium is 0.000 015 meters. How many meters can be counted by scientific counting

1.5 to the negative 5th power

We know that a, B, C and D are integers, and prove that: (a 2 + B 2) (C 2 + D 2) is the sum of two complete square numbers

It is proved that: (A2 + B2) (C2 + D2) = a2c2 + a2d2 + b2c2 + b2d2 = a2c2 + b2d2 + 2abcd-2abcd + a2d2 + b2c2 = (a2c2 + 2abcd + b2d2) + (a2d2-2abcd + b2c2) = (AC + BD) 2 + (BC AD) 2, so (A2 + B2) (C2 + D2) is the sum of two complete squares

A, B, C and D are integers. Prove that a ^ 2 * C ^ 2 + A ^ 2 * d ^ 2 + B ^ 2 * C ^ 2 + B ^ 2 * d ^ 2 must be the sum of the squares of two numbers

Dissolve the original form into
(a^2 *c^2+b^2 *d^2+2abcd)+(a^2 *d^2+b^2 *c^2-2abcd)
=(ac+bd)^2+(ad-bc)^2
The proof is over!

Among the seven numbers 1991199219931994199519961997, the number that cannot be written as the square difference of two natural numbers is______ ．

1994 is an even number, 1994 △ 4 = 498 2. Other numbers can be written as the square difference of two natural numbers: 1991 = 9962-9952, 1992 = 4992-4972, 1993 = 9972-9962, 1994 can't, 1995 = 9982-9972, 1996 = 5002-4982, 1997 = 9992-9982

Among the seven numbers 1991199219931994199519961997, the number that cannot be written as the square difference of two natural numbers is______ ．

1994 is an even number, 1994 △ 4 = 498 2. Other numbers can be written as the square difference of two natural numbers: 1991 = 9962-9952, 1992 = 4992-4972, 1993 = 9972-9962, 1994 can't, 1995 = 9982-9972, 1996 = 5002-4982, 1997 = 9992-9982

Is a = 1995 ^ 2x1995 ^ 2x1996 ^ 2 + 1996 ^ 2 a complete square

It should be a = 1995 & sup2; + 1995 & sup2; × 1996 & sup2; + 1996 & sup2; = (1996 & sup2; - 2 × 1996 × 1995 + 1995 & sup2;) + 2 × 1996 × 1995 + 1995 & sup2; = (1996-1995) & sup2; + 2 × 1996 × 1995 + 1995 & sup2; = 1 + 2 × 1996 × 1995 + 1

-What is 30 to the 31st power?

(-30)^31 = -6.1767339628395 * 10 45

What is the remainder of (the 31st power of 30 + the 30th power of 31) divided by 13?

The remainder of 30 divided by 13 is 431, the remainder of 13 is 5, the remainder of 4 divided by 31 + 5 divided by 13 is 4 ^ 31 = 16 ^ 15 * 45 ^ 30 = 125 ^ 10, the remainder of 3 ^ 15 * 4 + 8 ^ 10 divided by 13 is 3 ^ 15 * 4 = 27 ^ 5 * 48 ^ 10 = 64 ^ 5, the remainder of 4 + 12 ^ 5 divided by 13 is 12 ^ 5 = 144 * 144 * 12

What's the tenth power of 30

1.405116

The third power of X + the fourth power of X is equal to?

It's the one you said. It can't be merged